We read your photo as:

b. 8x + 3 = c. 20+ x = 28 d. 3 = 24/x 3a. Factorize the following a. 2amv + 2anv - 2amv b. ab + 4xy - 2bx - 2ay c. mn - 6xy - 3nx + 3m- Bbi. Solve 3(3x−1) = 4( ii. Solve 5(x + 11)+2(2x

Mathematics

ScanSolve AI Answer

Answers

2 parts
a

2anv

b

(a - 2x)(b - 2y)

Step-by-step solution

6 steps

Here are the solutions to the problems you sent:

Problem d:
Solve 3=24x3 = \frac{24}{x}

Step 1: Multiply both sides by xx.

3x=243x = 24

Step 2: Divide both sides by 3.

x=243x = \frac{24}{3} x=8x = 8

The solution is x=8\boxed{x = 8}.

. Factorize the following:

Part a· 1 step

2amv+2anv−2amv2amv + 2anv - 2amv

  1. Combine like terms.

    (2amv−2amv)+2anv(2amv - 2amv) + 2anv 0+2anv0 + 2anv 2anv2anv

    The factored expression is 2anv\boxed{2anv}.

Part b(a - 2x)(b - 2y)

ab+4xy−2bx−2ayab + 4xy - 2bx - 2ay

  1. Rearrange terms to group common factors.

    ab−2bx−2ay+4xyab - 2bx - 2ay + 4xy
  2. Factor out common factors from each group.

    b(a−2x)−2y(a−2x)b(a - 2x) - 2y(a - 2x)
  3. Factor out the common binomial (a−2x)(a - 2x).

    (a−2x)(b−2y)(a - 2x)(b - 2y)

    The factored expression is (a−2x)(b−2y)\boxed{(a - 2x)(b - 2y)}.

Part c(i)· 1 step

3(3x−1)=4(...)3(3x - 1) = 4(...)

mn−6xy−3nx+3mymn - 6xy - 3nx + 3my

This expression does not appear to be factorable by grouping as written. It is possible there is a typo in the question.

Problem 3bi. Solve:

  1. Distribute the 3 on the left side.

    9x−3=4(...)9x - 3 = 4(...)

    The equation is incomplete as the terms on the right side of the equality are missing. Therefore, it cannot be solved.

Part c(ii)· 1 step

5(x+11)+2(2x...)5(x + 11) + 2(2x...)

  1. Distribute the 5 on the first term.

    5x+55+2(2x...)5x + 55 + 2(2x...)

    The equation is incomplete as the terms in the second parenthesis and the right side of the equality are missing. Therefore, it cannot be solved.

Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question