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Solve the following equations for x: a) 3(6+7x)+2(1−5x)=42 b) 2(x+3)−3(x−1)=12

Mathematics

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Answers

2 parts
a
2
b
-3

Step-by-step solution

8 steps

Part a· 4 steps

  1. Distribute the numbers outside the parentheses.

    3(6)+3(7x)+2(1)+2(−5x)=423(6) + 3(7x) + 2(1) + 2(-5x) = 42 18+21x+2−10x=4218 + 21x + 2 - 10x = 42
  2. Combine like terms.

    (21x−10x)+(18+2)=42(21x - 10x) + (18 + 2) = 42 11x+20=4211x + 20 = 42
  3. Subtract 20 from both sides to isolate the term with xx.

    11x=42−2011x = 42 - 20 11x=2211x = 22
  4. Divide by 11 to solve for xx.

    x=2211x = \frac{22}{11} x=2x = \boxed{2}

Part b-3

  1. Distribute the numbers outside the parentheses.

    Remember to distribute the −3-3 to both terms inside the second parenthesis.

    2(x)+2(3)−3(x)−3(−1)=122(x) + 2(3) - 3(x) - 3(-1) = 12 2x+6−3x+3=122x + 6 - 3x + 3 = 12
  2. Combine like terms.

    (2x−3x)+(6+3)=12(2x - 3x) + (6 + 3) = 12 −x+9=12-x + 9 = 12
  3. Subtract 9 from both sides to isolate the term with xx.

    −x=12−9-x = 12 - 9 −x=3-x = 3
  4. Multiply both sides by −1-1 to solve for xx.

    x=−3x = \boxed{-3}
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