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Solve the following equations for x: 1) 6(3x-4) = -4(x+6) 2) 4 − 7x = 3x + 4 3) 6x − 2 = 4x − 1 4) 3(2x+5) = 2(x−5) + 13

Mathematics

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Here are the solutions for the given equations:

  1. 6(3x−4)=−4(x+6)6(3x-4) = -4(x+6)
  1. Distribute the numbers on both sides of the equation.

    18x−24=−4x−2418x - 24 = -4x - 24
  2. Add 4x4x to both sides to collect xx terms.

    18x+4x−24=−2418x + 4x - 24 = -24 22x−24=−2422x - 24 = -24
  3. Add 24 to both sides to isolate the xx term.

    22x=−24+2422x = -24 + 24 22x=022x = 0
  4. Divide by 22 to solve for xx.

    x=022x = \frac{0}{22} x=0x = 0

    The truth set is {0}\boxed{\{0\}}.

    1. 4−7x=3x+44 - 7x = 3x + 4
  5. Add 7x7x to both sides to collect xx terms.

    4=3x+7x+44 = 3x + 7x + 4 4=10x+44 = 10x + 4
  6. Subtract 4 from both sides to isolate the xx term.

    4−4=10x4 - 4 = 10x 0=10x0 = 10x
  7. Divide by 10 to solve for xx.

    x=010x = \frac{0}{10} x=0x = 0

    The truth set is {0}\boxed{\{0\}}.

    1. 6x−2=4x−16x - 2 = 4x - 1
  8. Subtract 4x4x from both sides to collect xx terms.

    6x−4x−2=−16x - 4x - 2 = -1 2x−2=−12x - 2 = -1
  9. Add 2 to both sides to isolate the xx term.

    2x=−1+22x = -1 + 2 2x=12x = 1
  10. Divide by 2 to solve for xx.

    x=12x = \frac{1}{2}

    The truth set is {12}\boxed{\left\{\frac{1}{2}\right\}}.

    1. 3(2x+5)=2(x−5)+133(2x+5) = 2(x-5) + 13
  11. Distribute the numbers on both sides of the equation.

    6x+15=2x−10+136x + 15 = 2x - 10 + 13 6x+15=2x+36x + 15 = 2x + 3
  12. Subtract 2x2x from both sides to collect xx terms.

    6x−2x+15=36x - 2x + 15 = 3 4x+15=34x + 15 = 3
  13. Subtract 15 from both sides to isolate the xx term.

    4x=3−154x = 3 - 15 4x=−124x = -12
  14. Divide by 4 to solve for xx.

    x=−124x = \frac{-12}{4} x=−3x = -3

    The truth set is {−3}\boxed{\{-3\}}.

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