b. Aziza has GHC 5.00, Ahmed has GHC 6.50 and Koby has GHC 2.50 more than Aziza and Ahmed together. Find the total amount of money the three boys have altogether. c. Simplify i. 5(3)/(4) - 2(7)/(8) + 1(1)/(2) ii. (8)/(9) x (4)/(6)

$$\text{Aziza's money} = \text{GH¢ } 5.00$$ $$\text{Ahmed's money} = \text{GH¢ } 6.50$$ $$\text{Aziza and Ahmed together} = \text{GH¢ } 5.00 + \text{GH¢ } 6.50 = \text{GH¢ } 11.50$$

Koby has GH¢ 2.50 more than Aziza and Ahmed together.

$$\text{Koby's money} = \text{GH¢ } 11.50 + \text{GH¢ } 2.50 = \text{GH¢ } 14.00$$

$$\text{Total money} = \text{Aziza's money} + \text{Ahmed's money} + \text{Koby's money}$$ $$\text{Total money} = \text{GH¢ } 5.00 + \text{GH¢ } 6.50 + \text{GH¢ } 14.00 = \text{GH¢ } 25.50$$

The total amount of money the three boys have altogether is $\boxed{\text{GH¢ } 25.50}$.

$$5\frac{3}{4} = \frac{(5 \times 4) + 3}{4} = \frac{20 + 3}{4} = \frac{23}{4}$$ $$2\frac{7}{8} = \frac{(2 \times 8) + 7}{8} = \frac{16 + 7}{8} = \frac{23}{8}$$ $$1\frac{1}{2} = \frac{(1 \times 2) + 1}{2} = \frac{2 + 1}{2} = \frac{3}{2}$$

$$\frac{23}{4} - \frac{23}{8} + \frac{3}{2}$$ $$\frac{23 \times 2}{4 \times 2} - \frac{23}{8} + \frac{3 \times 4}{2 \times 4}$$ $$\frac{46}{8} - \frac{23}{8} + \frac{12}{8}$$

$$\frac{35}{8} = 4\frac{3}{8}$$

The simplified expression is $\boxed{4\frac{3}{8}}$.

$$\frac{32 \div 2}{54 \div 2} = \frac{16}{27}$$

The simplified expression is $\boxed{\frac{16}{27}}$.