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Determine the balances labelled as A and B on the statement. Write down as a unit ratio the ATM withdrawal on 3/8 to the cash deposit made on the same day.

Mathematics

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Part 4.1· 2 steps

To determine the balances labelled A and B

  1. Calculate balance A.

    Balance A is the balance after an ATM withdrawal of R300.00 on 3/8. The previous balance was R1,324.98.

    Balance A=R1,324.98−R300.00=R1,024.98\text{Balance A} = \text{R}1,324.98 - \text{R}300.00 = \text{R}1,024.98

  2. Calculate balance B.

    Balance B is the balance after a Medical Aid refund of R765.56 on 4/8. The previous balance was R3,839.00.

    Balance B=R3,839.00+R765.56=R4,604.56\text{Balance B} = \text{R}3,839.00 + \text{R}765.56 = \text{R}4,604.56

    The balances are:

    • A = R1,024.98
    • B = R4,604.56

Part 4.2· 3 steps

To write the ATM withdrawal on 3/8 to the cash deposit on the same day as a unit ratio

  1. Identify the values for the ATM withdrawal and cash deposit on 3/8.

    ATM withdrawal on 3/8 = R300.00
    Cash deposit on 3/8 = R3,000.00

  2. Form the ratio.

    ATM withdrawal:Cash deposit=300:3000\text{ATM withdrawal} : \text{Cash deposit} = 300 : 3000

  3. Simplify the ratio to a unit ratio by dividing both sides by the smaller value (300).

    300300:3000300\frac{300}{300} : \frac{3000}{300} 1:101 : 10

    The unit ratio of the ATM withdrawal on 3/8 to the cash deposit made on the same day is 1 : 10.

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