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CALCULUS (DIFFERENTIATION & INTEGRATION)

Mathematics

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1. CALCULUS (DIFFERENTIATION & INTEGRATION)

a) If y=(x2+3x−1)(2x−5)y = (x^2+3x-1)(2x-5), find dydx\frac{dy}{dx}.

  1. Identify the functions for the product rule.

    Let u=x2+3x−1u = x^2+3x-1 and v=2x−5v = 2x-5.

  2. Differentiate uu and vv with respect to xx.

    dudx=2x+3\frac{du}{dx} = 2x+3 dvdx=2\frac{dv}{dx} = 2
  3. Apply the product rule formula $\frac{dy}{dx} =

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