Can u find the area and including finding the missing angle

Mathematics

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2 parts
1

132 cm2\text{132 cm}^2

2

33.7∘33.7^\circ

To find the area of the compound figure and the missing angle 'x', we will break down the figure into simpler shapes and use trigonometric ratios.

Part 1: Finding the Area of the Compound Figure

We can decompose the figure into four basic shapes: three rectangles and one right-angled triangle.

  • Step 1: Identify the shapes and their dimensions.

    • Rectangle 1 (R1 - Bottom section): This rectangle spans the entire width of the base and has a height of 4 cm.
      • Width = 4 cm+8 cm+6 cm=18 cm4 \text{ cm} + 8 \text{ cm} + 6 \text{ cm} = 18 \text{ cm}
      • Height = 4 cm4 \text{ cm}
    • Rectangle 2 (R2 - Left section above R1): This rectangle is on the far left, above the 4 cm height of R1.
      • Width = 4 cm4 \text{ cm}
      • Height = 8 cm−4 cm=4 cm8 \text{ cm} - 4 \text{ cm} = 4 \text{ cm} (total height on left is 8 cm, 4 cm is part of R1)
    • Rectangle 3 (R3 - Middle section above R1): This rectangle is in the middle, above the 8 cm width segment.
      • Width = 8 cm8 \text{ cm}
      • Height = 4 cm4 \text{ cm}
    • Triangle 1 (T1 - Right section above R1): This is a right-angled triangle on the far right, above the 6 cm width segment.
      • Base = 6 cm6 \text{ cm}
      • Height = 4 cm4 \text{ cm}
  • Step 2: Calculate the area of each individual shape.

    • Area of R1: AR1=width×height=18 cm×4 cm=72 cm2A_{R1} = \text{width} \times \text{height} = 18 \text{ cm} \times 4 \text{ cm} = 72 \text{ cm}^2
    • Area of R2: AR2=width×height=4 cm×4 cm=16 cm2A_{R2} = \text{width} \times \text{height} = 4 \text{ cm} \times 4 \text{ cm} = 16 \text{ cm}^2
    • Area of R3: AR3=width×height=8 cm×4 cm=32 cm2A_{R3} = \text{width} \times \text{height} = 8 \text{ cm} \times 4 \text{ cm} = 32 \text{ cm}^2
    • Area of T1: AT1=12×base×height=12×6 cm×4 cm=12 cm2A_{T1} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 6 \text{ cm} \times 4 \text{ cm} = 12 \text{ cm}^2
  • Step 3: Calculate the total area. The total area of the compound figure is the sum of the areas of these individual shapes.

    Atotal=AR1+AR2+AR3+AT1A_{\text{total}} = A_{R1} + A_{R2} + A_{R3} + A_{T1} Atotal=72 cm2+16 cm2+32 cm2+12 cm2A_{\text{total}} = 72 \text{ cm}^2 + 16 \text{ cm}^2 + 32 \text{ cm}^2 + 12 \text{ cm}^2 Atotal=132 cm2A_{\text{total}} = 132 \text{ cm}^2

    The total area of the compound figure is 132 cm2\boxed{\text{132 cm}^2}.

Part 2: Finding the Missing Angle 'x'

Angle 'x' is located in the right-angled triangle (T1) on the right side of the figure.

  • Step 1: Identify the known sides relative to angle 'x'.

    • The side opposite to angle 'x' is the height of the triangle, which is 4 cm.
    • The side adjacent to angle 'x' is the base of the triangle, which is 6 cm.
  • Step 2: Use the tangent trigonometric ratio. The tangent of an angle in a right-angled triangle is the ratio of the length of the opposite side to the length of the adjacent side.

    tan⁡(x)=oppositeadjacent\tan(x) = \frac{\text{opposite}}{\text{adjacent}} tan⁡(x)=4 cm6 cm\tan(x) = \frac{4 \text{ cm}}{6 \text{ cm}} tan⁡(x)=23\tan(x) = \frac{2}{3}
  • Step 3: Calculate the angle 'x' using the inverse tangent function.

    x=arctan⁡(23)x = \arctan\left(\frac{2}{3}\right) x≈33.690067∘x \approx 33.690067^\circ
  • Step 4: Round the angle to one decimal place.

    x≈33.7∘x \approx 33.7^\circ

    The missing angle 'x' is 33.7∘\boxed{33.7^\circ}.

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