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Factorize 12r2 - 27y2, Factorize 1 - (a - b)2, Factorize 16x2 - (1 - y)2, Factorize Completely 3 - 12x2

Mathematics

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Here are the factorizations:

  1. Factorize 12r2−27y212r^2 - 27y^2
  1. Find the greatest common factor (GCF) of the terms.

    The GCF of 12 and 27 is 3.

    12r2−27y2=3(4r2−9y2)12r^2 - 27y^2 = 3(4r^2 - 9y^2)
  2. Recognize the difference of squares pattern, A2−B2=(A−B)(A+B)A^2 - B^2 = (A-B)(A+B).

    Here, A2=4r2  ⟹  A=2rA^2 = 4r^2 \implies A = 2r and B2=9y2  ⟹  B=3yB^2 = 9y^2 \implies B = 3y.

  3. Apply the difference of squares formula.

    3(4r2−9y2)=3((2r)2−(3y)2)=3(2r−3y)(2r+3y)3(4r^2 - 9y^2) = 3((2r)^2 - (3y)^2) = 3(2r - 3y)(2r + 3y)

    The factored expression is 3(2r−3y)(2r+3y)\boxed{3(2r - 3y)(2r + 3y)}.

    1. Factorize 1−(a−b)21 - (a-b)^2
  4. Recognize the difference of squares pattern, A2−B2=(A−B)(A+B)A^2 - B^2 = (A-B)(A+B).

    Here, A2=1  ⟹  A=1A^2 = 1 \implies A = 1 and B2=(a−b)2  ⟹  B=(a−b)B^2 = (a-b)^2 \implies B = (a-b).

  5. Apply the difference of squares formula.

    1−(a−b)2=(1−(a−b))(1+(a−b))1 - (a-b)^2 = (1 - (a-b))(1 + (a-b))
  6. Simplify the terms inside the parentheses.

    (1−a+b)(1+a−b)(1 - a + b)(1 + a - b)

    The factored expression is (1−a+b)(1+a−b)\boxed{(1 - a + b)(1 + a - b)}.

    1. Factorize 16x2−(1−y)216x^2 - (1-y)^2
  7. Recognize the difference of squares pattern, A2−B2=(A−B)(A+B)A^2 - B^2 = (A-B)(A+B).

    Here, A2=16x2  ⟹  A=4xA^2 = 16x^2 \implies A = 4x and B2=(1−y)2  ⟹  B=(1−y)B^2 = (1-y)^2 \implies B = (1-y).

  8. Apply the difference of squares formula.

    16x2−(1−y)2=(4x−(1−y))(4x+(1−y))16x^2 - (1-y)^2 = (4x - (1-y))(4x + (1-y))
  9. Simplify the terms inside the parentheses.

    (4x−1+y)(4x+1−y)(4x - 1 + y)(4x + 1 - y)

    The factored expression is (4x−1+y)(4x+1−y)\boxed{(4x - 1 + y)(4x + 1 - y)}.

    1. Factorize Completely 3−12x23 - 12x^2
  10. Find the greatest common factor (GCF) of the terms.

    The GCF of 3 and 12 is 3.

    3−12x2=3(1−4x2)3 - 12x^2 = 3(1 - 4x^2)
  11. Recognize the difference of squares pattern, A2−B2=(A−B)(A+B)A^2 - B^2 = (A-B)(A+B).

    Here, A2=1  ⟹  A=1A^2 = 1 \implies A = 1 and B2=4x2  ⟹  B=2xB^2 = 4x^2 \implies B = 2x.

  12. Apply the difference of squares formula.

    3(1−4x2)=3((1)2−(2x)2)=3(1−2x)(1+2x)3(1 - 4x^2) = 3((1)^2 - (2x)^2) = 3(1 - 2x)(1 + 2x)

    The completely factored expression is 3(1−2x)(1+2x)\boxed{3(1 - 2x)(1 + 2x)}.

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