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Complete the construction of triangle ABC.

Mathematics

ScanSolve AI Answer

Answer

34.6∘34.6^\circ

Step-by-step solution

2 steps
  1. Complete the construction of triangle ABC.

    • Draw a line segment AB of length 5 cm5 \text{ cm}.
    • At point A, construct an angle of 120∘120^\circ. This is done by drawing an arc centered at A, then marking 60∘60^\circ and 120∘120^\circ along this arc. Draw a ray from A through the 120∘120^\circ mark.
    • With point B as the center, open the compass to a radius of 10 cm10 \text{ cm}. Draw an arc that intersects the ray from A. Label the intersection point C.
    • Draw a line segment from B to C to complete the triangle ABC.
  2. Measure the size of angle ABC.

    Using a protractor, measure the angle at vertex B, which is ∠ABC\angle ABC.
    From the provided figure, the measured angle is 34.6∘34.6^\circ.

    To verify this measurement using trigonometry:
    Given AB=5 cmAB = 5 \text{ cm}, BC=10 cmBC = 10 \text{ cm}, and ∠BAC=120∘\angle BAC = 120^\circ.
    Using the Sine Rule:

    BCsin⁡(∠BAC)=ABsin⁡(∠BCA)\frac{BC}{\sin(\angle BAC)} = \frac{AB}{\sin(\angle BCA)} 10sin⁡(120∘)=5sin⁡(∠BCA)\frac{10}{\sin(120^\circ)} = \frac{5}{\sin(\angle BCA)} sin⁡(∠BCA)=5×sin⁡(120∘)10\sin(\angle BCA) = \frac{5 \times \sin(120^\circ)}{10} sin⁡(∠BCA)=12×32\sin(\angle BCA) = \frac{1}{2} \times \frac{\sqrt{3}}{2} sin⁡(∠BCA)=34\sin(\angle BCA) = \frac{\sqrt{3}}{4} ∠BCA=arcsin⁡(34)≈25.66∘\angle BCA = \arcsin\left(\frac{\sqrt{3}}{4}\right) \approx 25.66^\circ

    The sum of angles in a triangle is 180∘180^\circ:

    ∠ABC=180∘−∠BAC−∠BCA\angle ABC = 180^\circ - \angle BAC - \angle BCA ∠ABC=180∘−120∘−25.66∘\angle ABC = 180^\circ - 120^\circ - 25.66^\circ ∠ABC=34.34∘\angle ABC = 34.34^\circ

    The measured value of 34.6∘34.6^\circ is consistent with the calculated value, allowing for typical construction and measurement tolerances.

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