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Complete the following arithmetic problems, demonstrating properties of addition and subtraction, and solving a word problem.

Mathematics

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Answer

i
6

Step-by-step solution

5 steps
  1. Complete 3.1.1

    The equation is 11+8=8+‾11 + 8 = 8 + \underline{\hspace{1cm}}.
    This demonstrates the commutative property of addition (a+b=b+aa+b = b+a).

    11+8=8+1111 + 8 = 8 + \boxed{11}
  2. Complete 3.1.2

    The equation is C8+7C=1+‾C8 + 7C = 1 + \underline{\hspace{1cm}}.
    Assuming 'C' is a typographical error and the numbers are intended to be 8 and 7, similar to the simple arithmetic context of the other problems.

    8+7=1+‾8 + 7 = 1 + \underline{\hspace{1cm}} 15=1+‾15 = 1 + \underline{\hspace{1cm}}

    To find the missing number, subtract 1 from 15:

    15−1=1415 - 1 = 14 8+7=1+148 + 7 = 1 + \boxed{14}
  3. Complete 3.1.3

    The equation is 4−6=‾4 - 6 = \underline{\hspace{1cm}}.

    4−6=−24 - 6 = \boxed{-2}
  4. Write the number sentence and then solve for 3.2

    The problem states: "James has 13 apples and Kate has 7 apples less than James. How many apples does Kate have?"
    The number sentence is 13−713 - 7.

    i)

    13−7=613 - 7 = \boxed{6}

    ii)

    13−7=613 - 7 = 6

    This is correct.

  5. State True or False for 4.1

    The statement is C+6−3=8+0C + 6 - 3 = 8 + 0.
    Simplify both sides of the equation:
    Left side: C+6−3=C+3C + 6 - 3 = C + 3.
    Right side: 8+0=88 + 0 = 8.
    The statement becomes C+3=8C + 3 = 8.
    This is an equation, not a statement that is universally true or false without a defined value for 'C'. If 'C' is a variable, the statement is only true if C=5C=5. Since no value for 'C' is given, the statement is not always true. Therefore, as a general statement

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