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Complete the pattern for the given sequences: Sequence D (red), Sequence C (blue), Sequence D (green), and sequence a).

Mathematics

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Here are the solutions to the patterns and the word problem.

Train Car Sequences

  • Sequence D (red cars): 538, 547, 556, \text{___}, \text{___}, \text{___}

    • Pattern: Add 9 to the previous number (547−538=9547 - 538 = 9, 556−547=9556 - 547 = 9).
    • Next numbers: 556+9=565556 + 9 = 565 565+9=574565 + 9 = 574 574+9=583574 + 9 = 583
    • The completed sequence is: 538,547,556,565,574,583538, 547, 556, \boxed{565}, \boxed{574}, \boxed{583}.
  • Sequence C (blue cars): 729, 629, 529, \text{___}, \text{___}, \text{___}

    • Pattern: Subtract 100 from the previous number (629−729=−100629 - 729 = -100, 529−629=−100529 - 629 = -100).
    • Next numbers: 529−100=429529 - 100 = 429 429−100=329429 - 100 = 329 329−100=229329 - 100 = 229
    • The completed sequence is: 729,629,529,429,329,229729, 629, 529, \boxed{429}, \boxed{329}, \boxed{229}.
  • Sequence D (green cars): 347, 354, 361, \text{___}, \text{___}, \text{___}

    • Pattern: Add 7 to the previous number (354−347=7354 - 347 = 7, 361−354=7361 - 354 = 7).
    • Next numbers: 361+7=368361 + 7 = 368 368+7=375368 + 7 = 375 375+7=382375 + 7 = 382
    • The completed sequence is: 347,354,361,368,375,382347, 354, 361, \boxed{368}, \boxed{375}, \boxed{382}.

Complete the pattern.

  • a) 373, 374, 376, \text{___}, \text{___}, \text{___}

    • Pattern: Add 1, then add 2, then add 3, and so on. (The amount added increases by 1 each time).
    • Next numbers: 376+3=379376 + 3 = 379 379+4=383379 + 4 = 383 383+5=388383 + 5 = 388
    • The completed sequence is: 373,374,376,379,383,388373, 374, 376, \boxed{379}, \boxed{383}, \boxed{388}.
  • b) 650, 653, 659, \text{___}, \text{___}, \text{___}

    • Pattern: Add 3, then add 6, then add 12, and so on. (The amount added doubles each time).
    • Next numbers: 659+12=671659 + 12 = 671 671+24=695671 + 24 = 695 695+48=743695 + 48 = 743
    • The completed sequence is: 650,653,659,671,695,743650, 653, 659, \boxed{671}, \boxed{695}, \boxed{743}.
  • c) 298, 303, 313, \text{___}, \text{___}, \text{___}

    • Pattern: Add 5, then add 10, then add 20, and so on. (The amount added doubles each time).
    • Next numbers: 313+20=333313 + 20 = 333 333+40=373333 + 40 = 373 373+80=453373 + 80 = 453
    • The completed sequence is: 298,303,313,333,373,453298, 303, 313, \boxed{333}, \boxed{373}, \boxed{453}.
  • d) 642, 644, 648, \text{___}, \text{___}, \text{___}

    • Pattern: Add 2, then add 4, then add 8, and so on. (The amount added doubles each time).
    • Next numbers: 648+8=656648 + 8 = 656 656+16=672656 + 16 = 672 672+32=704672 + 32 = 704
    • The completed sequence is: 642,644,648,656,672,704642, 644, 648, \boxed{656}, \boxed{672}, \boxed{704}.
  • e) 589, 593, 601, \text{___}, \text{___}, \text{___}

    • Pattern: Add 4, then add 8, then add 16, and so on. (The amount added doubles each time).
    • Next numbers: 601+16=617601 + 16 = 617 617+32=649617 + 32 = 649 649+64=713649 + 64 = 713
    • The completed sequence is: 589,593,601,617,649,713589, 593, 601, \boxed{617}, \boxed{649}, \boxed{713}.
  • f) 461, 467, 479, \text{___}, \text{___}, \text{___}

    • Pattern: Add 6, then add 12, then add 24, and so on. (The amount added doubles each time).
    • Next numbers: 479+24=503479 + 24 = 503 503+48=551503 + 48 = 551 551+96=647551 + 96 = 647
    • The completed sequence is: 461,467,479,503,551,647461, 467, 479, \boxed{503}, \boxed{551}, \boxed{647}.

Collecting shells

James collects shells. Every day he picks up twice as many shells as the previous day. On the first day he picks up 7 shells. On the second day he picks up 14. How many shells would he collect on the ninth day?

This is a geometric sequence where the first term a1=7a_1 = 7 and the common ratio r=2r = 2.
The formula for the nn-th term of a geometric sequence is an=a1⋅rn−1a_n = a_1 \cdot r^{n-1}.

  1. Identify the given values.

    a1=7a_1 = 7 (shells on the first day)
    r=2r = 2 (twice as many as the previous day)
    n=9n = 9 (ninth day)

  2. Substitute the values into the formula.

    a9=7⋅29−1a_9 = 7 \cdot 2^{9-1} a9=7⋅28a_9 = 7 \cdot 2^8
  3. Calculate 282^8.

    28=2×2×2×2×2×2×2×2=2562^8 = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 = 256
  4. Calculate a9a_9.

    a9=7⋅256a_9 = 7 \cdot 256 a9=1792a_9 = 1792

    James would collect 1792\boxed{1792} shells on the ninth day.

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