Complete the table showing class limits, frequency, class boundaries, and class center. The first row is given as class limits 30-39, frequency 5, class boundaries 29.5-39.5, and class center 34.5. Th

The class width can be found from the class limits or class boundaries.
Using class limits: $39 - 30 + 1 = 10$.
Using class boundaries: $39.5 - 29.5 = 10$.
The class width is 10.

Assuming the classes are consecutive, the next class limit would start after the previous one ends.
The first class ends at 39. So, the next class starts at 40.
Since the class width is 10, the class limits for the second row are $40 - (40 + 10 - 1) = 40 - 49$.

Class boundaries are typically found by subtracting 0.5 from the lower class limit and adding 0.5 to the upper class limit.
Lower class boundary: $40 - 0.5 = 39.5$
Upper class boundary: $49 + 0.5 = 49.5$
So, the class boundaries are $39.5 - 49.5$.

The class center is the midpoint of the class limits or class boundaries.
Using class limits: $\frac{40 + 49}{2} = \frac{89}{2} = 44.5$.
Using class boundaries: $\frac{39.5 + 49.5}{2} = \frac{89}{2} = 44.5$.

The completed table is:

The missing values for the second row are:
Class limits: $\boxed{\text{40 - 49}}$
Class boundaries: $\boxed{\text{39.5 - 49.5}}$
Class center: $\boxed{\text{44.5}}$