This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
ScanSolve AI Answer
Welcome back — missed you this week. The image shows a table with class limits, frequency, class boundaries, and class center. The first row is partially filled. The student has written a calculation for the class center. The task is to complete the table. Based on the provided information, we need to find the missing values for the class limits, frequency, class boundaries, and class center. For the first row: Class limits: 30 - 39 Frequency: 5 Class boundaries: 29.5 - 39.5 Class center: 34.5 The student's calculation (30+39)/(2) is for the class center, which is (69)/(2) = 34.5. This matches the value in the table. The second row only has a frequency of 52. We need to infer the class limits, class boundaries, and class center for this row. Since only one row is given, we assume a consistent class width. Step 1: Determine the class width from the first row. The class width can be found from the class limits or class boundaries. Using class limits: 39 - 30 + 1 = 10. Using class boundaries: 39.5 - 29.5 = 10. The class width is 10. Step 2: Determine the class limits for the second row. Assuming the classes are consecutive, the next class limit would start after the previous one ends. The first class ends at 39. So, the next class starts at 40. Since the class width is 10, the class limits for the second row are 40 - (40 + 10 - 1) = 40 - 49. Step 3: Determine the class boundaries for the second row. Class boundaries are typically found by subtracting 0.5 from the lower class limit and adding 0.5 to the upper class limit. Lower class boundary: 40 - 0.5 = 39.5 Upper class boundary: 49 + 0.5 = 49.5 So, the class boundaries are 39.5 - 49.5. Step 4: Determine the class center for the second row. The class center is the midpoint of the class limits or class boundaries. Using class limits: (40 + 49)/(2) = (89)/(2) = 44.5. Using class boundaries: (39.5 + 49.5)/(2) = (89)/(2) = 44.5. The completed table is: | Class limits | Frequency | Class boundaries | Class center | | :----------- | :-------- | :--------------- | :----------- | | 30 - 39 | 5 | 29.5 - 39.5 | 34.5 | | 40 - 49 | 52 | 39.5 - 49.5 | 44.5 | The missing values for the second row are: Class limits: 40 - 49 Class boundaries: 39.5 - 49.5 Class center: 44.5 Send me the next one 📸