Using the provided frequency distribution table, determine the number of classes, the lower and upper class limits, the modal class, and the class mark and size for specific intervals.

Here's the solution to question 2:

2. (i) Frequency Distribution Table Analysis

a) The number of classes or intervals in the distribution is the count of rows in the "Mark (x)" column.
There are 5 classes.

• Number of classes: $\boxed{\text{5}}$

b) The lower class limit of the class 63-65 is the smallest value in that interval.

• Lower class limit: $\boxed{\text{63}}$

c) The upper class limit of the class 72-74 is the largest value in that interval.

• Upper class limit: $\boxed{\text{74}}$

d) The modal class is the class with the highest frequency. The highest frequency is 42, which corresponds to the class 66-68.

• Modal class: $\boxed{\text{66-68}}$

e) The class mark (or midpoint) of a class is calculated as $\frac{\text{Lower limit} + \text{Upper limit}}{2}$.
For the class 60-62, the class mark is $\frac{60 + 62}{2}$.

$$\frac{60 + 62}{2} = \frac{122}{2} = 61$$

• Class mark of 60-62: $\boxed{\text{61}}$

f) The class size (or class width) can be found by subtracting the lower limit of one class from the lower limit of the next class, or by counting the values in a class. For 60-62, the values are 60, 61, 62, so there are 3 values.
Alternatively, using class boundaries: The upper class boundary of 60-62 is 62.5, and the lower class boundary is 59.5. The class size is $62.5 - 59.5 = 3$.

• Class size: $\boxed{\text{3}}$

2. (ii) Functions

Given functions:
$f(x) = 2x + 3$
$g(x) = x - 3$

a) Find $f(2)$.