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Consider the following designs: (a) Write down the number of squares in design 1, 2, 3, 4, and 5. (b) Determine the number of squares in design n. (c) How many squares are there in design 20?

Mathematics

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Here are the solutions to the problems.

**** (unlabeled in the image, assuming it refers to the sequence from : $19; 16; 13; 10; ...$):

a) Determine the nth term and hence the 145th term.

  1. Identify the first term (aa) and common difference (dd) of the sequence.

    The first term is a=19a = 19.
    The common difference is d=16−19=−3d = 16 - 19 = -3.

  2. Use the formula for the nth term of an arithmetic sequence, Tn=a+(n−1)dT_n = a + (n-1)d.

    Tn=19+(n−1)(−3)T_n = 19 + (n-1)(-3) Tn=19−3n+3T_n = 19 - 3n + 3 Tn=22−3nT_n = 22 - 3n
  3. Calculate the 145th term by substituting n=145n=145 into the nth term formula.

    T145=22−3(145)T_{145} = 22 - 3(145) T145=22−435T_{145} = 22 - 435 T145=−413T_{145} = -413

    The nth term is 22−3n\boxed{22 - 3n} and the 145th term is −413\boxed{-413}.

    b) Determine which term of the number pattern equals -389.

  4. Set the nth term formula equal to -389 and solve for nn.

    22−3n=−38922 - 3n = -389
  5. Isolate nn.

    −3n=−389−22-3n = -389 - 22 −3n=−411-3n = -411 n=−411−3n = \frac{-411}{-3} n=137n = 137

    The 137th term is 137\boxed{137}.

    5. Consider the following designs:

    a) Write down the number of squares in design 1, 2, 3, 4, and 5.

  6. Count the squares in each given design.

    Design 1: 1 square
    Design 2: 3 squares
    Design 3: 5 squares
    Design 4: 7 squares

  7. Identify the pattern and determine the number of squares for design 5.

    The number of squares forms an arithmetic sequence with a common difference of 2.
    So, for design 5, the number of squares is 7+2=97 + 2 = 9.
    The number of squares for designs 1, 2, 3, 4, and 5 are 1,3,5,7,9\boxed{1, 3, 5, 7, 9}.

    b) Determine the number of squares in design n.

  8. Use the formula for the nth term of an arithmetic sequence, Tn=a+(n−1)dT_n = a + (n-1)d.

    The first term is a=1a = 1 and the common difference is d=2d = 2.

    Tn=1+(n−1)2T_n = 1 + (n-1)2
  9. Simplify the expression.

    Tn=1+2n−2T_n = 1 + 2n - 2 Tn=2n−1T_n = 2n - 1

    The number of squares in design n is 2n−1\boxed{2n - 1}.

    c) How many squares are there in design 20?

  10. Substitute n=20n=20 into the nth term formula Tn=2n−1T_n = 2n - 1.

    T20=2(20)−1T_{20} = 2(20) - 1
  11. Calculate the value.

    T20=40−1T_{20} = 40 - 1 T20=39T_{20} = 39

    There are 39\boxed{39} squares in design 20.

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