Find the value of x : sqrt(x + 36) = 9

Subtract 36 from both sides of the equation:

$$\sqrt{x} + 36 = 9$$ $$\sqrt{x} = 9 - 36$$ $$\sqrt{x} = -27$$

The principal square root of a real number cannot be negative. Since $\sqrt{x}$ must be greater than or equal to 0, and we have $\sqrt{x} = -27$, there is no real value of $x$ that satisfies this equation.

Therefore, there is no real solution for $x$.

$\text{No real solution}$