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Find the determinant of P

Mathematics

ScanSolve AI Answer

Answer

-9

Step-by-step solution

3 steps

Find the determinant of P:
Given the matrix P=(13243−1320)P = \begin{pmatrix} 1 & 3 & 2 \\ 4 & 3 & -1 \\ 3 & 2 & 0 \end{pmatrix}.

  1. Calculate the determinant using cofactor expansion along the first row.

    ∣P∣=1∣3−120∣−3∣4−130∣+2∣4332∣|P| = 1 \begin{vmatrix} 3 & -1 \\ 2 & 0 \end{vmatrix} - 3 \begin{vmatrix} 4 & -1 \\ 3 & 0 \end{vmatrix} + 2 \begin{vmatrix} 4 & 3 \\ 3 & 2 \end{vmatrix}
  2. Evaluate the 2×22 \times 2 determinants.

    ∣P∣=1((3)(0)−(−1)(2))−3((4)(0)−(−1)(3))+2((4)(2)−(3)(3))|P| = 1((3)(0) - (-1)(2)) - 3((4)(0) - (-1)(3)) + 2((4)(2) - (3)(3)) ∣P∣=1(0+2)−3(0+3)+2(8−9)|P| = 1(0 + 2) - 3(0 + 3) + 2(8 - 9) ∣P∣=1(2)−3(3)+2(−1)|P| = 1(2) - 3(3) + 2(-1)
  3. Perform the multiplications and additions/subtractions.

    ∣P∣=2−9−2|P| = 2 - 9 - 2 ∣P∣=−7−2|P| = -7 - 2 ∣P∣=−9|P| = -9

    The determinant of P is −9-9.

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