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Write down the given matrix P.

Mathematics

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Answer

(191867)\begin{pmatrix} 19 & 18 \\ 6 & 7 \end{pmatrix}

Step-by-step solution

4 steps
  1. Write down the given matrix PP.

    P=(4312)P = \begin{pmatrix} 4 & 3 \\ 1 & 2 \end{pmatrix}
  2. Calculate P2P^2 by multiplying PP by PP.

    P2=P×P=(4312)(4312)P^2 = P \times P = \begin{pmatrix} 4 & 3 \\ 1 & 2 \end{pmatrix} \begin{pmatrix} 4 & 3 \\ 1 & 2 \end{pmatrix}
  3. Perform the matrix multiplication.

    To find the element in row ii and column jj of the product matrix, multiply the elements of row ii of the first matrix by the corresponding elements of column jj of the second matrix and sum the products.

    • Top-left element (row 1, column 1):
    (4×4)+(3×1)=16+3=19(4 \times 4) + (3 \times 1) = 16 + 3 = 19
    • Top-right element (row 1, column 2):
    (4×3)+(3×2)=12+6=18(4 \times 3) + (3 \times 2) = 12 + 6 = 18
    • Bottom-left element (row 2, column 1):
    (1×4)+(2×1)=4+2=6(1 \times 4) + (2 \times 1) = 4 + 2 = 6
    • Bottom-right element (row 2, column 2):
    (1×3)+(2×2)=3+4=7(1 \times 3) + (2 \times 2) = 3 + 4 = 7
  4. Construct the resulting matrix P2P^2.

    P2=(191867)P^2 = \begin{pmatrix} 19 & 18 \\ 6 & 7 \end{pmatrix}

    The final answer is (191867)\begin{pmatrix} 19 & 18 \\ 6 & 7 \end{pmatrix}.

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