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Find the determinant of matrix B.

Mathematics

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Answer

-16

Step-by-step solution

4 steps

Ili kupata determinant ya matrix BB, tutatumia njia ya upanuzi wa cofactor.

Matrix iliyotolewa ni:

B=(123321202)B = \begin{pmatrix} 1 & 2 & 3 \\ 3 & 2 & 1 \\ 2 & 0 & 2 \end{pmatrix}
  1. Tumia fomula ya determinant kwa matrix ya 3×33 \times 3.

    Fomula ya determinant ya matrix (abcdefghi)\begin{pmatrix} a & b & c \\ d & e & f \\ g & h & i \end{pmatrix} ni a(ei−fh)−b(di−fg)+c(dh−eg)a(ei - fh) - b(di - fg) + c(dh - eg).

  2. Badilisha namba kutoka matrix BB kwenye fomula.

    ∣B∣=1⋅det⁡(2102)−2⋅det⁡(3122)+3⋅det⁡(3220)|B| = 1 \cdot \det \begin{pmatrix} 2 & 1 \\ 0 & 2 \end{pmatrix} - 2 \cdot \det \begin{pmatrix} 3 & 1 \\ 2 & 2 \end{pmatrix} + 3 \cdot \det \begin{pmatrix} 3 & 2 \\ 2 & 0 \end{pmatrix}
  3. Kokotoa determinants za matrix ndogo za 2×22 \times 2.

    det⁡(2102)=(2×2)−(1×0)=4−0=4\det \begin{pmatrix} 2 & 1 \\ 0 & 2 \end{pmatrix} = (2 \times 2) - (1 \times 0) = 4 - 0 = 4 det⁡(3122)=(3×2)−(1×2)=6−2=4\det \begin{pmatrix} 3 & 1 \\ 2 & 2 \end{pmatrix} = (3 \times 2) - (1 \times 2) = 6 - 2 = 4 det⁡(3220)=(3×0)−(2×2)=0−4=−4\det \begin{pmatrix} 3 & 2 \\ 2 & 0 \end{pmatrix} = (3 \times 0) - (2 \times 2) = 0 - 4 = -4
  4. Badilisha matokeo haya kwenye fomula kuu na kurahisisha.

    ∣B∣=1⋅(4)−2⋅(4)+3⋅(−4)|B| = 1 \cdot (4) - 2 \cdot (4) + 3 \cdot (-4) ∣B∣=4−8−12|B| = 4 - 8 - 12 ∣B∣=−4−12|B| = -4 - 12 ∣B∣=−16|B| = -16

    Determinant ya matrix BB ni:

    −16-16
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