In an examination, 70% of the candidates passed. If the number of candidates who passed was 350, how many failed?

Mathematics
In an examination, 70% of the candidates passed. If the number of candidates who passed was 350, how many failed?

ScanSolve AI Answer

Answer

230 L

Problem (1)

Step 1: The container contains an initial volume of 7070 L of solution with 250250 units of solute.

The target total volume is 300300 L.

Step 2: Let xx be the volume of pure water to add (in L). The equation is:

70+x=30070 + x = 300

Step 3: Solve for xx:

x=30070x = 300 - 70

x=230x = 230

The volume of pure water to add is 230230 L. The solute amount remains 250250 units.

230 L

Problem (2)

Step 1: The tap fills at a rate of 11 L in 1010 s.

The filling rate is:

r=1L10s=0.1 L/sr = \frac{1 L}{10 s} = 0.1 \text{ L/s}

Step 2: Time formula: t=Vrt = \frac{V}{r} or equivalently t=10Vt = 10V (in s, where VV in L).

For 2424 L:

t=10×24=240 st = 10 \times 24 = 240 \text{ s}

For 4040 L:

t=10×40=400 st = 10 \times 40 = 400 \text{ s}

For 5858 L:

t=10×58=580 st = 10 \times 58 = 580 \text{ s}

For 247247 L:

t=10×247=2470 st = 10 \times 247 = 2470 \text{ s}

240 s
400 s
580 s
2470 s

Was this helpful?

Need help with your own homework?

Get instant step-by-step solutions to any question. Free to start.

Ask Your Question

Still have questions?

Quick Answer

Problem (1) Step 1: The container contains an initial volume of 70 L of solution with 250 units of solute.

In an examination, 70% of the candidates passed. If the number of candidates who passed was 350, how many failed?
Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI Answer
Problem (1) Step 1: The container contains an initial volume of 70 L of solution with 250 units of solute. The target total volume is 300 L. Step 2: Let x be the volume of pure water to add (in L). The equation is: 70 + x = 300 Step 3: Solve for x: x = 300 - 70 x = 230 The volume of pure water to add is 230 L. The solute amount remains 250 units. 230 L Problem (2) Step 1: The tap fills at a rate of 1 L in 10 s. The filling rate is: r = 1 L10 s = 0.1 L/s Step 2: Time formula: t = (V)/(r) or equivalently t = 10V (in s, where V in L). For 24 L: t = 10 × 24 = 240 s For 40 L: t = 10 × 40 = 400 s For 58 L: t = 10 × 58 = 580 s For 247 L: t = 10 × 247 = 2470 s 240 s 400 s 580 s 2470 s