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Convert 36000 seconds to hours and solve a ratio problem with total mass 8 kg.

Mathematics

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2 parts
iii

36000 s=10 h\text{36000 s} = \text{10 h}

iv

2 kg\text{2 kg}

6 kg\text{6 kg}

Step-by-step solution

5 steps

Here are the solutions to the questions you sent:

Part iii· 2 steps

Convert 36000 seconds to hours.

  1. Recall the conversion factors for time.

    There are 60 seconds in 1 minute and 60 minutes in 1 hour.
    So, 1 hour = 60 minutes×60 seconds/minute=3600 seconds60 \text{ minutes} \times 60 \text{ seconds/minute} = 3600 \text{ seconds}.

  2. Convert 36000 seconds to hours.

    36000 s×1 h3600 s36000 \text{ s} \times \frac{1 \text{ h}}{3600 \text{ s}} =360003600 h= \frac{36000}{3600} \text{ h} =10 h= 10 \text{ h}

    The conversion is:

    36000 s=10 h\boxed{\text{36000 s} = \text{10 h}}

Part iv

2 kg\text{2 kg}

The ratio of mass of sugar to coffee was 1:3 respectively. The total mass was 8 kg.

  1. Determine the total number of ratio parts.

    The ratio of sugar to coffee is 1:31:3.
    Total parts = 1+3=41 + 3 = 4 parts.

  2. Calculate the mass represented by one part.

    Total mass = 8 kg8 \text{ kg}.
    Mass per part = Total massTotal parts=8 kg4=2 kg/part\frac{\text{Total mass}}{\text{Total parts}} = \frac{8 \text{ kg}}{4} = 2 \text{ kg/part}.

  3. Calculate the mass of sugar and coffee.

    Mass of sugar = 1 part×2 kg/part=2 kg1 \text{ part} \times 2 \text{ kg/part} = 2 \text{ kg}.
    Mass of coffee = 3 parts×2 kg/part=6 kg3 \text{ parts} \times 2 \text{ kg/part} = 6 \text{ kg}.

    The masses are:

    • Mass of sugar: 2 kg\boxed{\text{2 kg}}
    • Mass of coffee: 6 kg\boxed{\text{6 kg}}
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