We read your photo as:

How many bricks, each of size 25 cm × 13.5 cm × 6 cm, will be required to build a wall 5.4 m long, 5.4 m high and 33 cm thick?

Mathematics

ScanSolve AI Answer

Answer

88.2 kg\text{88.2 kg}

Step-by-step solution

4 steps
  1. Convert all dimensions to centimeters.

    Length (ll) = 1.05 m=1.05×100 cm=105 cm1.05 \text{ m} = 1.05 \times 100 \text{ cm} = 105 \text{ cm}
    Breadth (bb) = 70 cm70 \text{ cm}
    Height (hh) = 1.5 cm1.5 \text{ cm}

  2. Calculate the volume of the rectangular piece of iron.

    The formula for the volume of a cuboid is V=l×b×hV = l \times b \times h.

    V=105 cm×70 cm×1.5 cmV = 105 \text{ cm} \times 70 \text{ cm} \times 1.5 \text{ cm} V=7350 cm2×1.5 cmV = 7350 \text{ cm}^2 \times 1.5 \text{ cm} V=11025 cm3V = 11025 \text{ cm}^3
  3. Calculate the total weight of the iron piece in grams.

    Given that 1 cm31 \text{ cm}^3 of iron weighs 8 grams.

    Weight in grams=Volume×Weight per unit volume\text{Weight in grams} = \text{Volume} \times \text{Weight per unit volume} Weight in grams=11025 cm3×8gcm3\text{Weight in grams} = 11025 \text{ cm}^3 \times 8 \frac{\text{g}}{\text{cm}^3} Weight in grams=88200 g\text{Weight in grams} = 88200 \text{ g}
  4. Convert the total weight from grams to kilograms.

    We know that 1 kg=1000 g1 \text{ kg} = 1000 \text{ g}.

    Weight in kilograms=88200 g1000gkg\text{Weight in kilograms} = \frac{88200 \text{ g}}{1000 \frac{\text{g}}{\text{kg}}} Weight in kilograms=88.2 kg\text{Weight in kilograms} = 88.2 \text{ kg}

    The weight of the piece of iron is 88.2 kg\text{88.2 kg}.

Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp