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Express 56 as a product of its prime factors.

March 23, 2026Mathematics

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Answer

4 \frac{2}{3}

5 steps

Convert the mixed numbers to improper fractions.
$24 \frac{1}{2} = \frac{24 \times 2 + 1}{2} = \frac{49}{2}$ $5 \frac{1}{4} = \frac{5 \times 4 + 1}{4} = \frac{21}{4}$
Rewrite the division as multiplication by the reciprocal.
$24 \frac{1}{2} \div 5 \frac{1}{4} = \frac{49}{2} \div \frac{21}{4} = \frac{49}{2} \times \frac{4}{21}$
Multiply the fractions.
$\frac{49}{2} \times \frac{4}{21} = \frac{49 \times 4}{2 \times 21} = \frac{196}{42}$
Simplify the fraction $\frac{196}{42}$ .
Divide numerator and denominator by 14:
$\frac{196 \div 14}{42 \div 14} = \frac{14}{3}$
Convert $\frac{14}{3}$ to a mixed number.
$\frac{14}{3} = 4 \frac{2}{3}$
$\boxed{4 \frac{2}{3}}$

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