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State the coordinates at E, for which value of θ is the function increasing, and the range of the function?

Mathematics

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a.i) For the function y=cos⁡θ−1y = \cos\theta - 1

  1. Determine the coordinates at E.

    The point E represents the minimum value of the function. The minimum value of cos⁡θ\cos\theta is −1-1, which occurs at θ=180∘\theta = 180^\circ.
    Substituting this into the function:

    y=cos⁡(180∘)−1=−1−1=−2y = \cos(180^\circ) - 1 = -1 - 1 = -2

    The coordinates at E are (180∘,−2)\boxed{(180^\circ, -2)}.

  2. Determine the interval where the function is increasing.

    The function y=cos⁡θ−1y = \cos\theta - 1 is a vertical shift of y=cos⁡θy = \cos\theta. The increasing intervals for cos⁡θ\cos\theta are from 180∘180^\circ to 360∘360^\circ.
    The function is increasing for θ∈(180∘,360∘)\boxed{\theta \in (180^\circ, 360^\circ)}.

  3. Determine the range of the function.

    The range of cos⁡θ\cos\theta is [−1,1][-1, 1]. For y=cos⁡θ−1y = \cos\theta - 1, we subtract 1 from these values.
    The minimum value is −1−1=−2-1 - 1 = -2.
    The maximum value is 1−1=01 - 1 = 0.
    The range of the function is [−2,0]\boxed{[-2, 0]}.

    a.ii) For the function y=sin⁡θ+1y = \sin\theta + 1

  4. Determine the interval where the function is increasing.

    The function y=sin⁡θ+1y = \sin\theta + 1 is a vertical shift of y=sin⁡θy = \sin\theta. The increasing intervals for sin⁡θ\sin\theta are from 0∘0^\circ to 90∘90^\circ and from 270∘270^\circ to 360∘360^\circ.
    The function is increasing for θ∈(0∘,90∘)∪(270∘,360∘)\boxed{\theta \in (0^\circ, 90^\circ) \cup (270^\circ, 360^\circ)}.

  5. Determine the range of the function.

    The range of sin⁡θ\sin\theta is [−1,1][-1, 1]. For y=sin⁡θ+1y = \sin\theta + 1, we add 1 to these values.
    The minimum value is −1+1=0-1 + 1 = 0.
    The maximum value is 1+1=21 + 1 = 2.
    The range of the function is [0,2]\boxed{[0, 2]}.

    b.i) For the function y=sin⁡θ+2y = \sin\theta + 2

  6. Determine the coordinates at E.

    The point E represents the minimum value of the function. The minimum value of sin⁡θ\sin\theta is −1-1, which occurs at θ=270∘\theta = 270^\circ.
    Substituting this into the function:

    y=sin⁡(270∘)+2=−1+2=1y = \sin(270^\circ) + 2 = -1 + 2 = 1

    The coordinates at E are (270∘,1)\boxed{(270^\circ, 1)}.

  7. Determine the interval where the function is increasing.

    The function y=sin⁡θ+2y = \sin\theta + 2 is a vertical shift of y=sin⁡θy = \sin\theta. The increasing intervals for sin⁡θ\sin\theta are from 0∘0^\circ to 90∘90^\circ and from 270∘270^\circ to 360∘360^\circ.
    The function is increasing for θ∈(0∘,90∘)∪(270∘,360∘)\boxed{\theta \in (0^\circ, 90^\circ) \cup (270^\circ, 360^\circ)}.

  8. Determine the range of the function.

    The range of sin⁡θ\sin\theta is [−1,1][-1, 1]. For y=sin⁡θ+2y = \sin\theta + 2, we add 2 to these values.
    The minimum value is −1+2=1-1 + 2 = 1.
    The maximum value is 1+2=31 + 2 = 3.
    The range of the function is [1,3]\boxed{[1, 3]}.

    b.ii) For the function y=cos⁡θy = \cos\theta

  9. Determine the interval where the function is increasing.

    The standard cosine function y=cos⁡θy = \cos\theta increases from 180∘180^\circ to 360∘360^\circ.
    The function is increasing for θ∈(180∘,360∘)\boxed{\theta \in (180^\circ, 360^\circ)}.

  10. Determine the range of the function.

    The range of the standard cosine function y=cos⁡θy = \cos\theta is [−1,1]\boxed{[-1, 1]}.

    c.i) For the function y=2cos⁡θ+52y = 2\cos\theta + \frac{5}{2}

  11. Determine the coordinates at E.

    The point E represents the minimum value of the function. The minimum value of cos⁡θ\cos\theta is −1-1, which occurs at θ=180∘\theta = 180^\circ.
    Substituting this into the function:

    y=2cos⁡(180∘)+52=2(−1)+52=−2+52=−4+52=12y = 2\cos(180^\circ) + \frac{5}{2} = 2(-1) + \frac{5}{2} = -2 + \frac{5}{2} = \frac{-4+5}{2} = \frac{1}{2}

    The coordinates at E are (180∘,12)\boxed{(180^\circ, \frac{1}{2})}.

  12. Determine the interval where the function is increasing.

    The function y=2cos⁡θ+52y = 2\cos\theta + \frac{5}{2} is a vertical stretch and shift of y=cos⁡θy = \cos\theta. The increasing intervals for cos⁡θ\cos\theta are from 180∘180^\circ to 360∘360^\circ.
    The function is increasing for θ∈(180∘,360∘)\boxed{\theta \in (180^\circ, 360^\circ)}.

  13. Determine the range of the function.

    The range of cos⁡θ\cos\theta is [−1,1][-1, 1].
    For y=2cos⁡θy = 2\cos\theta, the range is [2(−1),2(1)]=[−2,2][2(-1), 2(1)] = [-2, 2].
    For y=2cos⁡θ+52y = 2\cos\theta + \frac{5}{2}, we add 52\frac{5}{2} to these values.
    The minimum value is −2+52=−4+52=12-2 + \frac{5}{2} = \frac{-4+5}{2} = \frac{1}{2}.
    The maximum value is 2+52=4+52=922 + \frac{5}{2} = \frac{4+5}{2} = \frac{9}{2}.
    The range of the function is [12,92]\boxed{[\frac{1}{2}, \frac{9}{2}]}.

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