Cosine rule formula

Mathematics

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Answer

a2=b2+c2−2bccos⁡(A)a^2 = b^2 + c^2 - 2bc \cos(A)

The Cosine Rule relates the lengths of the sides of a triangle to the cosine of one of its angles.

For a triangle with sides a,b,ca, b, c and angles A,B,CA, B, C opposite to those sides respectively:

To find a side:

a2=b2+c2−2bccos⁡(A)a^2 = b^2 + c^2 - 2bc \cos(A) b2=a2+c2−2accos⁡(B)b^2 = a^2 + c^2 - 2ac \cos(B) c2=a2+b2−2abcos⁡(C)c^2 = a^2 + b^2 - 2ab \cos(C)

To find an angle:

cos⁡(A)=b2+c2−a22bc\cos(A) = \frac{b^2 + c^2 - a^2}{2bc} cos⁡(B)=a2+c2−b22ac\cos(B) = \frac{a^2 + c^2 - b^2}{2ac} cos⁡(C)=a2+b2−c22ab\cos(C) = \frac{a^2 + b^2 - c^2}{2ab}
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