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GRADE 09 MATHEMATICS TERM 3 PRE TEST 8.2. Determine the following 8.2.1. 8.2.2. 8.2.3. 8.3. Use the following table to draw the histogram graph. QUESTION 9: PROBABILITY 9.1. A coin is tossed and a dice is rolled.

Mathematics

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Answer

158.5 cm\text{158.5 cm}

Step-by-step solution

3 steps

To find the median height for question 8.2.2:

  1. List the heights in ascending order.

    From the previous question, the heights in ascending order are:
    $132, 132, 141, 142, 155, 156, 161, 162, 163, 169, 170, 172$.

  2. Identify the number of data points.

    There are 12 heights, so n=12n = 12.

  3. Calculate the median.

    Since nn is an even number, the median is the average of the two middle values. These are the (n2)th(\frac{n}{2})^{th} and (n2+1)th(\frac{n}{2} + 1)^{th} values.
    The (122)th(\frac{12}{2})^{th} value is the 6th6^{th} value, which is 156.
    The (122+1)th(\frac{12}{2} + 1)^{th} value is the 7th7^{th} value, which is 161.

    Median=6th value+7th value2\text{Median} = \frac{6^{th} \text{ value} + 7^{th} \text{ value}}{2} Median=156+1612\text{Median} = \frac{156 + 161}{2} Median=3172\text{Median} = \frac{317}{2} Median=158.5 cm\text{Median} = 158.5 \text{ cm}

    The median height is 158.5 cm\text{158.5 cm}.

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