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Find the critical points alpha and beta by solving the given quadratic equation.

Mathematics

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2 parts
a

12 and 18\frac{1}{2} \text{ and } \frac{1}{8}

b

16y2−10y+1=016y^2 - 10y + 1 = 0

Step-by-step solution

6 steps

here's the solution for Item 1:

Part a· 2 steps

Write the inverse of each of the critical points α\alpha and β\beta.

  1. Find the critical points α\alpha and β\beta by solving the given quadratic equation.

    The project's progress is modeled by the equation:

    x2−10x+16=0x^2 - 10x + 16 = 0

    We can factor this quadratic equation:

    (x−2)(x−8)=0(x - 2)(x - 8) = 0

    The roots are x=2x = 2 and x=8x = 8.
    Let α=2\alpha = 2 and β=8\beta = 8.

  2. Write the inverse of each critical point.

    The inverse of α\alpha is 1α\frac{1}{\alpha}.

    1α=12\frac{1}{\alpha} = \frac{1}{2}

    The inverse of β\beta is 1β\frac{1}{\beta}.

    1β=18\frac{1}{\beta} = \frac{1}{8}

    The inverses of the critical points are 12 and 18\boxed{\frac{1}{2} \text{ and } \frac{1}{8}}.

Part b

16y2−10y+1=016y^2 - 10y + 1 = 0

Help Eli come up with an equation that models these inverse critical points.

  1. Identify the new roots.

    The new critical points (inverse critical points) are 12\frac{1}{2} and 18\frac{1}{8}.

  2. Calculate the sum of the new roots.

    Sum=12+18=48+18=58\text{Sum} = \frac{1}{2} + \frac{1}{8} = \frac{4}{8} + \frac{1}{8} = \frac{5}{8}
  3. Calculate the product of the new roots.

    Product=12×18=116\text{Product} = \frac{1}{2} \times \frac{1}{8} = \frac{1}{16}
  4. Form the new quadratic equation.

    A quadratic equation with roots r1r_1 and r2r_2 can be written as y2−(sum of roots)y+(product of roots)=0y^2 - (\text{sum of roots})y + (\text{product of roots}) = 0.

    y2−(58)y+(116)=0y^2 - \left(\frac{5}{8}\right)y + \left(\frac{1}{16}\right) = 0

    To eliminate fractions, multiply the entire equation by the least common multiple of the denominators (16):

    16(y2−58y+116)=16×016 \left(y^2 - \frac{5}{8}y + \frac{1}{16}\right) = 16 \times 0 16y2−10y+1=016y^2 - 10y + 1 = 0

    The equation that models these inverse critical points is 16y2−10y+1=0\boxed{16y^2 - 10y + 1 = 0}.

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