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d). (1)/(2) - (3)/(4) + (5)/(6) and d). 5(4)/(5) - 3(2)/(7)

Mathematics

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Answer

712\frac{7}{12}

218352\frac{18}{35}

Step-by-step solution

8 steps

Huu hapa utatuzi wa swali la kwanza (d):

  1. Tafuta Kigawo Kidogo Zaidi cha Pamoja (LCM) cha madhehebu 2, 4, na 6.

    LCM ya 2, 4, na 6 ni 12.

  2. Badilisha kila sehemu kuwa sehemu sawa na dhehebu la 12.

    12=1×62×6=612\frac{1}{2} = \frac{1 \times 6}{2 \times 6} = \frac{6}{12} 34=3×34×3=912\frac{3}{4} = \frac{3 \times 3}{4 \times 3} = \frac{9}{12} 56=5×26×2=1012\frac{5}{6} = \frac{5 \times 2}{6 \times 2} = \frac{10}{12}
  3. Fanya hesabu ya kujumlisha na kutoa.

    612−912+1012=6−9+1012=712\frac{6}{12} - \frac{9}{12} + \frac{10}{12} = \frac{6 - 9 + 10}{12} = \frac{7}{12}

    Jibu ni 712\boxed{\frac{7}{12}}.

    Huu hapa utatuzi wa swali la pili (d):

  4. Badilisha namba mchanganyiko kuwa sehemu zisizofaa.

    545=(5×5)+45=25+45=2955\frac{4}{5} = \frac{(5 \times 5) + 4}{5} = \frac{25 + 4}{5} = \frac{29}{5} 327=(3×7)+27=21+27=2373\frac{2}{7} = \frac{(3 \times 7) + 2}{7} = \frac{21 + 2}{7} = \frac{23}{7}
  5. Tafuta Kigawo Kidogo Zaidi cha Pamoja (LCM) cha madhehebu 5 na 7.

    LCM ya 5 na 7 ni 5×7=355 \times 7 = 35.

  6. Badilisha kila sehemu kuwa sehemu sawa na dhehebu la 35.

    295=29×75×7=20335\frac{29}{5} = \frac{29 \times 7}{5 \times 7} = \frac{203}{35} 237=23×57×5=11535\frac{23}{7} = \frac{23 \times 5}{7 \times 5} = \frac{115}{35}
  7. Fanya hesabu ya kutoa.

    20335−11535=203−11535=8835\frac{203}{35} - \frac{115}{35} = \frac{203 - 115}{35} = \frac{88}{35}
  8. Badilisha sehemu isiyofaa kuwa namba mchanganyiko.

    8835=21835\frac{88}{35} = 2\frac{18}{35}

    Jibu ni 21835\boxed{2\frac{18}{35}}.

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