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State the definition of the derivative from first principles.

Mathematics

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Here are the derivatives of the given functions using first principles:

1) f(x)=cos⁡xf(x) = \cos x

Step 1: State the definition of the derivative from first principles.

f′(x)=lim⁡h→0f(x+h)−f(x)hf'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h}

Step 2: Substitute f(x)=cos⁡xf(x) = \cos x and f(x+h)=cos⁡(x+h)f(x+h) = \cos(x+h) into the formula.

f′(x)=lim⁡h→0cos⁡(x+h)−cos⁡xhf'(x) = \lim_{h \to 0} \frac{\cos(x+h) - \cos x}{h}

Step 3: Apply the sum-to-product trigonometric identity cos⁡A−cos⁡B=−2sin⁡(A+B2)sin⁡(A−B2)\cos A - \cos B = -2 \sin\left(\frac{A+B}{2}\right) \sin\left(\frac{A-B}{2}\right).

f′(x)=lim⁡h→0−2sin⁡(x+h+x2)sin⁡(x+h−x2)hf'(x) = \lim_{h \to 0} \frac{-2 \sin\left(\frac{x+h+x}{2}\right) \sin\left(\frac{x+h-x}{2}\right)}{h} f′(x)=lim⁡h→0−2sin⁡(x+h2)sin⁡(h2)hf'(x) = \lim_{h \to 0} \frac{-2 \sin\left(x+\frac{h}{2}\right) \sin\left(\frac{h}{2}\right)}{h}

Step 4: Rearrange the expression to use the fundamental limit lim⁡θ→0sin⁡θθ=1\lim_{\theta \to 0} \frac{\sin \theta}{\theta} = 1.

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