Find the derivative of y = sqrt((x2 + 1)/(x2 - 1)).
|Mathematics
Find the derivative of y = sqrt((x2 + 1)/(x2 - 1)).
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Answer
dxdy=(x2−1)3/2x2+1−2x
Morning — let's get this done.
: Find the derivative of y=x2−1x2+1.
We can rewrite the function as y=(x2−1x2+1)1/2.
We use the chain rule: dxdy=21u−1/2dxdu, where u=x2−1x2+1.
Step 1: Find dxdu using the quotient rule.
Let p=x2+1 and q=x2−1.
Then p′=2x and q′=2x.
dxdu=q2p′q−pq′=(x2−1)2(2x)(x2−1)−(x2+1)(2x)dxdu=(x2−1)22x3−2x−(2x3+2x)dxdu=(x2−1)22x3−2x−2x3−2xdxdu=(x2−1)2−4x
Step 2: Apply the chain rule.
dxdy=21(x2−1x2+1)−1/2⋅((x2−1)2−4x)dxdy=21(x2+1x2−1)1/2⋅((x2−1)2−4x)dxdy=21x2+1x2−1⋅(x2−1)2−4xdxdy=x2+1(x2−1)2−2xx2−1
Simplify the powers of (x2−1): (x2−1)2=(x2−1)3/2(x2−1)1/2.
dxdy=x2+1(x2−1)3/2−2x
The derivative is:
dxdy=(x2−1)3/2x2+1−2x
: Find the derivative of f(x)=ln(1+exex).
Step 1: Simplify the function using logarithm properties.
f(x)=ln(ex)−ln(1+ex)f(x)=x−ln(1+ex)
Step 2: Differentiate f(x) with respect to x.
f′(x)=dxd(x)−dxd(ln(1+ex))f′(x)=1−1+ex1⋅dxd(1+ex)f′(x)=1−1+ex1⋅exf′(x)=1−1+exex
Combine the terms:
f′(x)=1+ex1+ex−exf′(x)=1+ex1
The derivative is:
f′(x)=1+ex1
: Find the derivative of y=xlnx.
We use logarithmic differentiation.
Step 1: Take the natural logarithm of both sides.
lny=ln(xlnx)
Use the logarithm property ln(ab)=blna:
lny=(lnx)(lnx)lny=(lnx)2
Step 2: Differentiate both sides with respect to x implicitly.
y1dxdy=2(lnx)⋅dxd(lnx)y1dxdy=2(lnx)⋅x1
Step 3: Solve for dxdy.
dxdy=y⋅x2lnx
Substitute y=xlnx back into the equation:
dxdy=xlnx⋅x2lnx
Using the exponent rule anam=am−n:
dxdy=2xlnx−1lnx
The derivative is:
dxdy=2xlnx−1lnx
: Find the derivative of y=(sinx)cosx.
We use logarithmic differentiation.
Step 1: Take the natural logarithm of both sides.
lny=ln((sinx)cosx)
Use the logarithm property ln(ab)=blna:
lny=(cosx)(ln(sinx))
Step 2: Differentiate both sides with respect to x implicitly. Use the product rule on the right side.
y1dxdy=dxd(cosx)⋅ln(sinx)+cosx⋅dxd(ln(sinx))
We know dxd(cosx)=−sinx.
For dxd(ln(sinx)), use the chain rule: sinx1⋅dxd(sinx)=sinx1⋅cosx=cotx.
So,
y1dxdy=(−sinx)(ln(sinx))+(cosx)(cotx)
Step 3: Solve for dxdy.
dxdy=y(−sinxln(sinx)+cosxcotx)
Substitute y=(sinx)cosx back into the equation:
dxdy=(sinx)cosx(−sinxln(sinx)+sinxcos2x)
The derivative is:
dxdy=(sinx)cosx(sinxcos2x−sinxln(sinx))
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ScanSolve AI Answer
Morning — let's get this done. Problem 1: Find the derivative of y = sqrt((x^2 + 1)/(x^2 - 1)). We can rewrite the function as y = ((x^2 + 1)/(x^2 - 1))^1/2. We use the chain rule: (dy)/(dx) = (1)/(2)u^-1/2 (du)/(dx), where u = (x^2 + 1)/(x^2 - 1). Step 1: Find (du)/(dx) using the quotient rule. Let p = x^2 + 1 and q = x^2 - 1. Then p' = 2x and q' = 2x. (du)/(dx) = (p'q - pq')/(q^2) = ((2x)(x^2 - 1) - (x^2 + 1)(2x))/((x^2 - 1)^2) (du)/(dx) = (2x^3 - 2x - (2x^3 + 2x))/((x^2 - 1)^2) (du)/(dx) = (2x^3 - 2x - 2x^3 - 2x)/((x^2 - 1)^2) (du)/(dx) = (-4x)/((x^2 - 1)^2) Step 2: Apply the chain rule. (dy)/(dx) = (1)/(2)((x^2 + 1)/(x^2 - 1))^-1/2 · ((-4x)/((x^2 - 1)^2)) (dy)/(dx) = (1)/(2)((x^2 - 1)/(x^2 + 1))^1/2 · ((-4x)/((x^2 - 1)^2)) (dy)/(dx) = (1)/(2) sqrt(x^2 - 1)sqrt(x^2 + 1) · (-4x)/((x^2 - 1)^2) (dy)/(dx) = -2x sqrt(x^2 - 1)sqrt(x^2 + 1) (x^2 - 1)^2 Simplify the powers of (x^2 - 1): (x^2 - 1)^2 = (x^2 - 1)^3/2 (x^2 - 1)^1/2. (dy)/(dx) = (-2x)/(sqrt(x^2 + 1) (x^2 - 1)^3/2) The derivative is: (dy)/(dx) = (-2x)/((x^2 - 1)^3/2)sqrt(x^2 + 1) Problem 2: Find the derivative of f(x) = ((e^x)/(1 + e^x)). Step 1: Simplify the function using logarithm properties. f(x) = (e^x) - (1 + e^x) f(x) = x - (1 + e^x) Step 2: Differentiate f(x) with respect to x. f'(x) = (d)/(dx)(x) - (d)/(dx)((1 + e^x)) f'(x) = 1 - (1)/(1 + e^x) · (d)/(dx)(1 + e^x) f'(x) = 1 - (1)/(1 + e^x) · e^x f'(x) = 1 - (e^x)/(1 + e^x) Combine the terms: f'(x) = (1 + e^x - e^x)/(1 + e^x) f'(x) = (1)/(1 + e^x) The derivative is: f'(x) = (1)/(1 + e^x) Problem 3: Find the derivative of y = x^ x. We use logarithmic differentiation. Step 1: Take the natural logarithm of both sides. y = (x^ x) Use the logarithm property (a^b) = b a: y = ( x)( x) y = ( x)^2 Step 2: Differentiate both sides with respect to x implicitly. (1)/(y) (dy)/(dx) = 2( x) · (d)/(dx)( x) (1)/(y) (dy)/(dx) = 2( x) · (1)/(x) Step 3: Solve for (dy)/(dx). (dy)/(dx) = y · (2 x)/(x) Substitute y = x^ x back into the equation: (dy)/(dx) = x^ x · (2 x)/(x) Using the exponent rule (a^m)/(a^n) = a^m-n: (dy)/(dx) = 2x^ x - 1 x The derivative is: (dy)/(dx) = 2x^ x - 1 x Problem 4: Find the derivative of y = ( x)^ x. We use logarithmic differentiation. Step 1: Take the natural logarithm of both sides. y = (( x)^ x) Use the logarithm property (a^b) = b a: y = ( x)(( x)) Step 2: Differentiate both sides with respect to x implicitly. Use the product rule on the right side. (1)/(y) (dy)/(dx) = (d)/(dx)( x) · ( x) + x · (d)/(dx)(( x)) We know (d)/(dx)( x) = - x. For (d)/(dx)(( x)), use the chain rule: (1)/( x) · (d)/(dx)( x) = (1)/( x) · x = x. So, (1)/(y) (dy)/(dx) = (- x)(( x)) + ( x)( x) Step 3: Solve for (dy)/(dx). (dy)/(dx) = y ( - x ( x) + x x ) Substitute y = ( x)^ x back into the equation: (dy)/(dx) = ( x)^ x ( - x ( x) + (^2 x)/( x) ) The derivative is: (dy)/(dx) = ( x)^ x ( (^2 x)/( x) - x ( x) )