We read your photo as:

Evaluate the determinant: | -2 -1 0 | | 3 0 1 | | 0 -3 2 |

Mathematics

ScanSolve AI Answer

Answer

0

Step-by-step solution

3 steps

यहाँ दिए गए सारणिक का मान इस प्रकार है:

भाग (iii): सारणिक का मान ज्ञात कीजिए

दिए गए सारणिक का मान ज्ञात करना है:

∣0−1−21032−30∣\begin{vmatrix} 0 & -1 & -2 \\ 1 & 0 & 3 \\ 2 & -3 & 0 \end{vmatrix}
  1. सारणिक का मान पहली पंक्ति (R1R_1) के अनुदिश सह-खंड विस्तार (cofactor expansion) का उपयोग करके ज्ञात कीजिए।

    ∣0−1−21032−30∣=0⋅∣03−30∣−(−1)⋅∣1320∣+(−2)⋅∣102−3∣\begin{vmatrix} 0 & -1 & -2 \\ 1 & 0 & 3 \\ 2 & -3 & 0 \end{vmatrix} = 0 \cdot \begin{vmatrix} 0 & 3 \\ -3 & 0 \end{vmatrix} - (-1) \cdot \begin{vmatrix} 1 & 3 \\ 2 & 0 \end{vmatrix} + (-2) \cdot \begin{vmatrix} 1 & 0 \\ 2 & -3 \end{vmatrix}
  2. 2×22 \times 2 सारणिकों का मान ज्ञात कीजिए।

    ∣03−30∣=(0)(0)−(3)(−3)=0−(−9)=9\begin{vmatrix} 0 & 3 \\ -3 & 0 \end{vmatrix} = (0)(0) - (3)(-3) = 0 - (-9) = 9 ∣1320∣=(1)(0)−(3)(2)=0−6=−6\begin{vmatrix} 1 & 3 \\ 2 & 0 \end{vmatrix} = (1)(0) - (3)(2) = 0 - 6 = -6 ∣102−3∣=(1)(−3)−(0)(2)=−3−0=−3\begin{vmatrix} 1 & 0 \\ 2 & -3 \end{vmatrix} = (1)(-3) - (0)(2) = -3 - 0 = -3
  3. इन मानों को मुख्य विस्तार में प्रतिस्थापित कीजिए।

    =0(9)+1(−6)−2(−3)= 0(9) + 1(-6) - 2(-3) =0−6+6= 0 - 6 + 6 =0= 0

    सारणिक का मान है: 0

Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp