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Devoir à Domicile - 3 APIC

Mathematics

ScanSolve AI Answer

Answer

A=16+322A = 16 + \frac{3\sqrt{2}}{2}

Step-by-step solution

4 steps

سأقوم بحل التمرين الأول، الجزء 1.أ.

  1. نبدأ بتبسيط التعبير AA.

    A=16+(23)2+6×32A = \sqrt{16} + (2\sqrt{3})^2 + \sqrt{6} \times \frac{\sqrt{3}}{2}
  2. نحسب قيمة 16\sqrt{16} ونبسط (23)2(2\sqrt{3})^2.

    16=4\sqrt{16} = 4 (23)2=22×(3)2=4×3=12(2\sqrt{3})^2 = 2^2 \times (\sqrt{3})^2 = 4 \times 3 = 12
  3. نبسط الجزء الأخير من التعبير 6×32\sqrt{6} \times \frac{\sqrt{3}}{2}.

    6×32=6×32=182\sqrt{6} \times \frac{\sqrt{3}}{2} = \frac{\sqrt{6 \times 3}}{2} = \frac{\sqrt{18}}{2} 182=9×22=322\frac{\sqrt{18}}{2} = \frac{\sqrt{9 \times 2}}{2} = \frac{3\sqrt{2}}{2}
  4. نجمع الأجزاء المبسطة للحصول على قيمة AA.

    A=4+12+322A = 4 + 12 + \frac{3\sqrt{2}}{2} A=16+322A = 16 + \frac{3\sqrt{2}}{2}
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