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Diana and Rahima start running on a circular track at the same time. Diana completes one round in 48 minutes, and Rahima completes one round in 36 minutes. If they both start at 8:06 a.m. from the sta

Mathematics

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Part 4· 4 steps

  1. Find the least common multiple (LCM) of the times Diana and Rahima take to complete one round.

    This will be the time after which they meet again at the starting point.
    Diana's time =48 minutes= 48 \text{ minutes}
    Rahima's time =36 minutes= 36 \text{ minutes}

    Prime factorization of 48:

    48=2×24=2×2×12=2×2×2×6=24×3148 = 2 \times 24 = 2 \times 2 \times 12 = 2 \times 2 \times 2 \times 6 = 2^4 \times 3^1

    Prime factorization of 36:

    36=2×18=2×2×9=22×3236 = 2 \times 18 = 2 \times 2 \times 9 = 2^2 \times 3^2
  2. Calculate the LCM of 48 and 36.

    LCM(48,36)=2max⁡(4,2)×3max⁡(1,2)=24×32=16×9=144 minutes\text{LCM}(48, 36) = 2^{\max(4,2)} \times 3^{\max(1,2)} = 2^4 \times 3^2 = 16 \times 9 = 144 \text{ minutes}
  3. Convert the total time in minutes to hours and minutes.

    144 minutes=14460 hours=2 hours and 24 minutes144 \text{ minutes} = \frac{144}{60} \text{ hours} = 2 \text{ hours and } 24 \text{ minutes}

    (Since 2×60=1202 \times 60 = 120, and 144−120=24144 - 120 = 24)

  4. Add this time to the starting time to find when they will meet again.

    Starting time =8:06 a.m.= 8:06 \text{ a.m.}
    Time to meet again =2 hours 24 minutes= 2 \text{ hours } 24 \text{ minutes}
    Meeting time =8:06 a.m.+2 hours 24 minutes=10:30 a.m.= 8:06 \text{ a.m.} + 2 \text{ hours } 24 \text{ minutes} = 10:30 \text{ a.m.}

    They will meet again at the starting point at 10:30 a.m.

Part 5

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