We read your photo as:

Differentiate the following functions with respect to x: a) y = x b) y = -x2 + 3 c) y = x3/3 + x2/2 + x d) y = 3x7 − 7x3 + 21x2 e) y = x4/4 - x3/3 + x2/2 - x + 3 f) y = sqrt(x5)

Mathematics

ScanSolve AI Answer

Step-by-step solution

14 steps

Part (A)

a) y=xy = x

  1. Apply the power rule ddx(xn)=nxn−1\frac{d}{dx}(x^n) = nx^{n-1}.

    dydx=1⋅x1−1=1⋅x0=1\frac{dy}{dx} = 1 \cdot x^{1-1} = 1 \cdot x^0 = 1

    The derivative is 1\boxed{\mathbf{1}}.

    b) y=−x2+3y = -x^2 + 3

  2. Differentiate each term using the power rule and constant rule.

    dydx=−2x2−1+0=−2x\frac{dy}{dx} = -2x^{2-1} + 0 = -2x

    The derivative is −2x\boxed{\mathbf{-2x}}.

    c) y=x33+x22+xy = \frac{x^3}{3} + \frac{x^2}{2} + x

  3. Differentiate each term using the power rule.

    dydx=13(3x3−1)+12(2x2−1)+1\frac{dy}{dx} = \frac{1}{3}(3x^{3-1}) + \frac{1}{2}(2x^{2-1}) + 1
  4. Simplify the expression.

    dydx=x2+x+1\frac{dy}{dx} = x^2 + x + 1

    The derivative is x2+x+1\boxed{\mathbf{x^2 + x + 1}}.

    d) y=3x7−7x3+21x2y = 3x^7 - 7x^3 + 21x^2

  5. Differentiate each term using the power rule.

    dydx=3(7x7−1)−7(3x3−1)+21(2x2−1)\frac{dy}{dx} = 3(7x^{7-1}) - 7(3x^{3-1}) + 21(2x^{2-1})
  6. Simplify the expression.

    dydx=21x6−21x2+42x\frac{dy}{dx} = 21x^6 - 21x^2 + 42x

    The derivative is 21x6−21x2+42x\boxed{\mathbf{21x^6 - 21x^2 + 42x}}.

    e) y=x44−x33+x22−x+3y = \frac{x^4}{4} - \frac{x^3}{3} + \frac{x^2}{2} - x + 3

  7. Differentiate each term using the power rule and constant rule.

    dydx=14(4x4−1)−13(3x3−1)+12(2x2−1)−1+0\frac{dy}{dx} = \frac{1}{4}(4x^{4-1}) - \frac{1}{3}(3x^{3-1}) + \frac{1}{2}(2x^{2-1}) - 1 + 0
  8. Simplify the expression.

    dydx=x3−x2+x−1\frac{dy}{dx} = x^3 - x^2 + x - 1

    The derivative is x3−x2+x−1\boxed{\mathbf{x^3 - x^2 + x - 1}}.

    f) y=x5y = \sqrt{x^5}

  9. Rewrite the function using fractional exponents.

    y=x5/2y = x^{5/2}
  10. Apply the power rule.

    dydx=52x52−1=52x32\frac{dy}{dx} = \frac{5}{2}x^{\frac{5}{2}-1} = \frac{5}{2}x^{\frac{3}{2}}

    The derivative is 52x3/2\boxed{\mathbf{\frac{5}{2}x^{3/2}}}.

    g) y=1x2/5y = \frac{1}{x^{2/5}}

  11. Rewrite the function using negative exponents.

    y=x−2/5y = x^{-2/5}
  12. Apply the power rule.

    dydx=−25x−25−1=−25x−75\frac{dy}{dx} = -\frac{2}{5}x^{-\frac{2}{5}-1} = -\frac{2}{5}x^{-\frac{7}{5}}
  13. Rewrite with positive exponents.

    dydx=−25x7/5\frac{dy}{dx} = -\frac{2}{5x^{7/5}}

    The derivative is −25x7/5\boxed{\mathbf{-\frac{2}{5x^{7/5}}}}.

    Part (B)

    a) U=(2x+3)2U = (2x + 3)^2

  14. Apply the chain rule.

    Let u=2x+3u = 2x+3.

    dUdx=2(2x+3)2−1⋅ddx(2x+3)\frac{dU}{dx} = 2(2x+3)^{2-1} \cdot \frac{d}{dx}(2x+3)

    Step

Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question