Differentiation

Mathematics

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Answer

f′(x)=12x3−4x+5f'(x) = 12x^3 - 4x + 5

Step-by-step solution

3 steps

Differentiation is a fundamental concept in calculus that measures how a function changes as its input changes. It helps us find the rate of change of a function.

1. Definition of the Derivative
The derivative of a function f(x)f(x) with respect to xx, denoted as f′(x)f'(x) or dydx\frac{dy}{dx}, is defined by the limit:

f′(x)=lim⁡h→0f(x+h)−f(x)hf'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h}

This limit represents the slope of the tangent line to the graph of f(x)f(x) at any point xx.

2. Basic Differentiation Rules

  • Constant Rule: The derivative of a constant is zero. If f(x)=cf(x) = c, where cc is a constant, then

    ddx(c)=0\frac{d}{dx}(c) = 0
  • Power Rule: The derivative of xnx^n is nxn−1nx^{n-1}. If f(x)=xnf(x) = x^n, where nn is any real number, then

    ddx(xn)=nxn−1\frac{d}{dx}(x^n) = nx^{n-1}
  • Constant Multiple Rule: The derivative of a constant times a function is the constant times the derivative of the function. If f(x)=c⋅g(x)f(x) = c \cdot g(x), where cc is a constant, then

    ddx(c⋅g(x))=c⋅ddx(g(x))\frac{d}{dx}(c \cdot g(x)) = c \cdot \frac{d}{dx}(g(x))
  • Sum/Difference Rule: The derivative of a sum or difference of functions is the sum or difference of their derivatives. If f(x)=g(x)±h(x)f(x) = g(x) \pm h(x), then

    ddx(g(x)±h(x))=ddx(g(x))±ddx(h(x))\frac{d}{dx}(g(x) \pm h(x)) = \frac{d}{dx}(g(x)) \pm \frac{d}{dx}(h(x))

Example: Find the derivative of f(x)=3x4−2x2+5x−7f(x) = 3x^4 - 2x^2 + 5x - 7.

  1. Apply the Sum/Difference Rule.

    ddx(3x4−2x2+5x−7)=ddx(3x4)−ddx(2x2)+ddx(5x)−ddx(7)\frac{d}{dx}(3x^4 - 2x^2 + 5x - 7) = \frac{d}{dx}(3x^4) - \frac{d}{dx}(2x^2) + \frac{d}{dx}(5x) - \frac{d}{dx}(7)
  2. Apply the Constant Multiple Rule and Power Rule to each term.

    ddx(3x4)=3⋅4x4−1=12x3\frac{d}{dx}(3x^4) = 3 \cdot 4x^{4-1} = 12x^3 ddx(2x2)=2⋅2x2−1=4x1=4x\frac{d}{dx}(2x^2) = 2 \cdot 2x^{2-1} = 4x^1 = 4x ddx(5x)=5⋅1x1−1=5x0=5⋅1=5\frac{d}{dx}(5x) = 5 \cdot 1x^{1-1} = 5x^0 = 5 \cdot 1 = 5 ddx(7)=0\frac{d}{dx}(7) = 0
  3. Combine the results.

    f′(x)=12x3−4x+5−0f'(x) = 12x^3 - 4x + 5 - 0 f′(x)=12x3−4x+5f'(x) = \boxed{12x^3 - 4x + 5}
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