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Calculate the distance covered by a train traveling at 4 km/hr from 9:30 am to 12:00 noon. List three properties each of a rectangle and a square. Calculate the total weight of 115.2 kg of maize, 242

Mathematics

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Section B

1.a)

  1. Calculate the time duration.

    The train starts at 9:30 am and travels until 12:00 noon.
    Time duration = 12:00 noon - 9:30 am = 2 hours 30 minutes.

  2. Convert the time duration to hours.

    2 hours 30 minutes=2+3060 hours=2+0.5 hours=2.5 hours2 \text{ hours } 30 \text{ minutes} = 2 + \frac{30}{60} \text{ hours} = 2 + 0.5 \text{ hours} = 2.5 \text{ hours}
  3. Calculate the distance covered.

    Given speed = 4 km/hr.
    Distance = Speed ×\times Time

    Distance=4 km/hr×2.5 hours=10 km\text{Distance} = 4 \text{ km/hr} \times 2.5 \text{ hours} = 10 \text{ km}

    The distance covered by the train is 10 km\boxed{\text{10 km}}.

    1.b)
    Three properties of a rectangle:

    • Opposite sides are equal in length and parallel.
    • All four interior angles are right angles (90∘90^\circ).
    • The diagonals bisect each other and are equal in length.

    Three properties of a square:

    • All four sides are equal in length.
    • All four interior angles are right angles (90∘90^\circ).
    • Opposite sides are parallel.

    2.a)

  4. Convert all weights to kilograms (kg).

    Maize: 115.2 kg
    Beans: 242 kg
    Rice: 142000 g

    142000 g×1 kg1000 g=142 kg142000 \text{ g} \times \frac{1 \text{ kg}}{1000 \text{ g}} = 142 \text{ kg}
  5. Calculate the total weight.

    Total weight = Weight of maize + Weight of beans + Weight of rice

    Total weight=115.2 kg+242 kg+142 kg=499.2 kg\text{Total weight} = 115.2 \text{ kg} + 242 \text{ kg} + 142 \text{ kg} = 499.2 \text{ kg}

    The total weight is 499.2 kg\boxed{\text{499.2 kg}}.

    2.b)

  6. Convert seconds to minutes.

    There are 60 seconds in 1 minute.

    60 seconds=1 minute60 \text{ seconds} = 1 \text{ minute}
  7. Convert minutes to hours.

    There are 60 minutes in 1 hour.

    1 minute=160 hour1 \text{ minute} = \frac{1}{60} \text{ hour}

    Therefore, 60 seconds is equal to 160 hour\boxed{\frac{1}{60} \text{ hour}}.

    3.a)

  8. Convert all volumes to the same unit (cm³).

    Given volume 1: 2 litres

    2 litres×1000 cm31 litre=2000 cm32 \text{ litres} \times \frac{1000 \text{ cm}^3}{1 \text{ litre}} = 2000 \text{ cm}^3

    Given volume 2: 800 cm³

  9. Calculate the total volume.

    Total volume = 2000 cm³ + 800 cm³ = 2800 cm³

  10. Divide the total volume among 7 traders.

    Volume per trader = Total volumeNumber of traders\frac{\text{Total volume}}{\text{Number of traders}}

    Volume per trader=2800 cm37=400 cm3\text{Volume per trader} = \frac{2800 \text{ cm}^3}{7} = 400 \text{ cm}^3

    Each trader receives 400 cm3\boxed{\text{400 cm}^3}.

    3.b)
    Three properties of a cube:

    • It has 6 faces, and all faces are squares of equal size.
    • It has 12 edges, and all edges are of equal length.
    • It has 8 vertices (corners).

    4.

  11. Ensure all dimensions are in the same unit (meters).

    Length = 80 m
    Width = 30 cm

    30 cm×1 m100 cm=0.3 m30 \text{ cm} \times \frac{1 \text{ m}}{100 \text{ cm}} = 0.3 \text{ m}

    Depth = 8 m

  12. Calculate the volume of the water in the pool.

    The pool is a cuboid, so its volume is given by Length ×\times Width ×\times Depth.

    Volume=80 m×0.3 m×8 m=24 m2×8 m=192 m3\text{Volume} = 80 \text{ m} \times 0.3 \text{ m} \times 8 \text{ m} = 24 \text{ m}^2 \times 8 \text{ m} = 192 \text{ m}^3

    The volume of the water in the pool is 192 m3\boxed{\text{192 m}^3}.

    5.a)

  13. Calculate the area of the rectangle.

    Length = 8128\frac{1}{2} m = 8.5 m
    Width = 3123\frac{1}{2} m = 3.5 m
    Area of rectangle = Length ×\times Width

    Arearectangle=8.5 m×3.5 m=29.75 m2\text{Area}_{\text{rectangle}} = 8.5 \text{ m} \times 3.5 \text{ m} = 29.75 \text{ m}^2
  14. Calculate the area of the right-angled triangle.

    Base = 16 cm
    Height = 18 cm
    Area of triangle = 12×Base×Height\frac{1}{2} \times \text{Base} \times \text{Height}

    Areatriangle=12×16 cm×18 cm=8 cm×18 cm=144 cm2\text{Area}_{\text{triangle}} = \frac{1}{2} \times 16 \text{ cm} \times 18 \text{ cm} = 8 \text{ cm} \times 18 \text{ cm} = 144 \text{ cm}^2

    The area of the rectangle is 29.75 m2\boxed{\text{29.75 m}^2} and the area of the triangle is 144 cm2\boxed{\text{144 cm}^2}.

    5.b)

  15. Convert mixed fractions to improper fractions.

    134=1×4+34=741\frac{3}{4} = \frac{1 \times 4 + 3}{4} = \frac{7}{4} 112=1×2+12=321\frac{1}{2} = \frac{1 \times 2 + 1}{2} = \frac{3}{2} 213=2×3+13=732\frac{1}{3} = \frac{2 \times 3 + 1}{3} = \frac{7}{3}
  16. Find a common denominator for 4, 2, and 3.

    The least common multiple (LCM) is 12.

    74=7×34×3=2112\frac{7}{4} = \frac{7 \times 3}{4 \times 3} = \frac{21}{12} 32=3×62×6=1812\frac{3}{2} = \frac{3 \times 6}{2 \times 6} = \frac{18}{12} 73=7×43×4=2812\frac{7}{3} = \frac{7 \times 4}{3 \times 4} = \frac{28}{12}
  17. Add the fractions.

    2112+1812+2812=21+18+2812=6712\frac{21}{12} + \frac{18}{12} + \frac{28}{12} = \frac{21 + 18 + 28}{12} = \frac{67}{12}
  18. Convert the improper fraction back to a mixed number.

    6712=5 with a remainder of 7  ⟹  5712\frac{67}{12} = 5 \text{ with a remainder of } 7 \implies 5\frac{7}{12}

    The simplified expression is 5712\boxed{5\frac{7}{12}}.

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