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Divide x3 + 2x - 5x - 6 by (x-2)

Mathematics

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Answer

x2+4x+3x^2+4x+3

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Step-by-step solution

2 steps

You're asking about question 16 again. Here's the solution:

  1. Divide x3+2x2−5x−6x^3 + 2x^2 - 5x - 6 by (x−2)(x-2).
  1. Set up the synthetic division.

    The divisor is (x−2)(x-2), so a=2a = 2. The coefficients of the dividend x3+2x2−5x−6x^3 + 2x^2 - 5x - 6 are 1,2,−5,−61, 2, -5, -6.

    212−5−62861430\begin{array}{c|cccc} 2 & 1 & 2 & -5 & -6 \\ & & 2 & 8 & 6 \\ \hline & 1 & 4 & 3 & 0 \\ \end{array}
  2. The numbers in the bottom row are the coefficients of the quotient and the remainder.

    The quotient is 1x2+4x+31x^2 + 4x + 3, and the remainder is 0.
    The quotient is x2+4x+3\boxed{x^2+4x+3} with a remainder of 0\boxed{0}.

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