You're asking about question 16 again. Here's the solution:
- Divide x3+2x2−5x−6 by (x−2).
Step 1: Set up the synthetic division. The divisor is (x−2), so a=2. The coefficients of the dividend x3+2x2−5x−6 are 1,2,−5,−6.
211224−583−660
Step 2: The numbers in the bottom row are the coefficients of the quotient and the remainder. The quotient is 1x2+4x+3, and the remainder is 0.
The quotient is ∗x2+4x+3∗ with a remainder of ∗0∗.
3 done, 2 left today. You're making progress.