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Draw graphs of the lines passing through the given points and determine the angle between each pair of lines.

Mathematics

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Answer

6\text{6}

Step-by-step solution

4 steps

Huu hapa ni ufumbuzi wa swali la 5:

Ili kutatua swali hili "kwa kuchora", tutatumia kanuni za mteremko wa mistari iliyo wima (perpendicular lines) kwenye ndege ya Cartesian. Mistari miwili ikiwa wima, bidhaa ya miteremko yao ni −1-1.

  1. Tafuta mteremko wa mstari wa kwanza (L1).

    Mstari wa kwanza unapita kwenye pointi (−1,1)(-1, 1) na (3,2)(3, 2).
    Kanuni ya mteremko m=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1}.

    m1=2−13−(−1)=13+1=14m_1 = \frac{2 - 1}{3 - (-1)} = \frac{1}{3 + 1} = \frac{1}{4}

    Mteremko wa mstari wa kwanza ni 14\frac{1}{4}.

  2. Tafuta mteremko wa mstari wa pili (L2).

    Mstari wa pili unapita kwenye pointi (2,−2)(2, -2) na (0,m)(0, m).

    m2=m−(−2)0−2=m+2−2m_2 = \frac{m - (-2)}{0 - 2} = \frac{m + 2}{-2}

    Mteremko wa mstari wa pili ni m+2−2\frac{m + 2}{-2}.

  3. Tumia masharti ya mistari iliyo wima.

    Kwa kuwa mistari hiyo miwili ni wima, bidhaa ya miteremko yao ni −1-1.

    m1⋅m2=−1m_1 \cdot m_2 = -1 14⋅m+2−2=−1\frac{1}{4} \cdot \frac{m + 2}{-2} = -1
  4. Tatua kwa mm.

    m+2−8=−1\frac{m + 2}{-8} = -1

    Panua pande zote mbili kwa −8-8:

    m+2=(−1)×(−8)m + 2 = (-1) \times (-8) m+2=8m + 2 = 8

    Toa 2 kutoka pande zote mbili:

    m=8−2m = 8 - 2 m=6m = 6

    Thamani ya mm ni 6\boxed{\text{6}}.

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