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Calculate the angles in the figure below.

Mathematics

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Here are the solutions to the problems:

1) Calculate the angles in the figure below.

a) Calculate α\alpha

  1. Identify the known sides relative to angle α\alpha.

    The side opposite α\alpha is 3.
    The side adjacent to α\alpha is 4.

  2. Use the tangent function.

    tan⁡(α)=oppositeadjacent\tan(\alpha) = \frac{\text{opposite}}{\text{adjacent}} tan⁡(α)=34\tan(\alpha) = \frac{3}{4}
  3. Calculate α\alpha.

    α=arctan⁡(34)\alpha = \arctan\left(\frac{3}{4}\right) α≈36.87∘\alpha \approx 36.87^\circ

    The angle is \boxed{\text{36.87^\circ}}.

    b) Calculate β\beta

  4. Identify the known sides relative to angle β\beta.

    The side opposite β\beta is 2.
    The side adjacent to β\beta is 7.

  5. Use the tangent function.

    tan⁡(β)=oppositeadjacent\tan(\beta) = \frac{\text{opposite}}{\text{adjacent}} tan⁡(β)=27\tan(\beta) = \frac{2}{7}
  6. Calculate β\beta.

    β=arctan⁡(27)\beta = \arctan\left(\frac{2}{7}\right) β≈15.95∘\beta \approx 15.95^\circ

    The angle is \boxed{\text{15.95^\circ}}.

    c) Calculate ϕ\phi

  7. Identify the known sides relative to angle ϕ\phi.

    The side opposite ϕ\phi is 4.
    The hypotenuse is 5.

  8. Use the sine function.

    sin⁡(ϕ)=oppositehypotenuse\sin(\phi) = \frac{\text{opposite}}{\text{hypotenuse}} sin⁡(ϕ)=45\sin(\phi) = \frac{4}{5}
  9. Calculate ϕ\phi.

    ϕ=arcsin⁡(45)\phi = \arcsin\left(\frac{4}{5}\right) ϕ≈53.13∘\phi \approx 53.13^\circ

    The angle is \boxed{\text{53.13^\circ}}.

    2) Find the lettered sides in the figure below.

    a) Find xx

  10. Identify the known angle and sides relative to xx.

    The angle is 30∘30^\circ.
    The side adjacent to 30∘30^\circ is 4.
    The hypotenuse is xx.

  11. Use the cosine function.

    cos⁡(30∘)=adjacenthypotenuse\cos(30^\circ) = \frac{\text{adjacent}}{\text{hypotenuse}} cos⁡(30∘)=4x\cos(30^\circ) = \frac{4}{x}
  12. Solve for xx.

    x=4cos⁡(30∘)x = \frac{4}{\cos(30^\circ)} x=432x = \frac{4}{\frac{\sqrt{3}}{2}} x=83x = \frac{8}{\sqrt{3}} x=833x = \frac{8\sqrt{3}}{3} x≈4.62x \approx 4.62

    The side length is 4.62\boxed{\text{4.62}}.

    b) Find yy

  13. Identify the known angle and sides relative to yy.

    The angle is 47∘47^\circ.
    The side opposite 47∘47^\circ is yy.
    The side adjacent to 47∘47^\circ is 5.

  14. Use the tangent function.

    tan⁡(47∘)=oppositeadjacent\tan(47^\circ) = \frac{\text{opposite}}{\text{adjacent}} tan⁡(47∘)=y5\tan(47^\circ) = \frac{y}{5}
  15. Solve for yy.

    y=5×tan⁡(47∘)y = 5 \times \tan(47^\circ) y≈5×1.0724y \approx 5 \times 1.0724 y≈5.36y \approx 5.36

    The side length is 5.36\boxed{\text{5.36}}.

    c) Find zz

  16. Identify the known angle and sides relative to zz.

    The angle is 52∘52^\circ.
    The side opposite 52∘52^\circ is zz.
    The hypotenuse is 7.

  17. Use the sine function.

    sin⁡(52∘)=oppositehypotenuse\sin(52^\circ) = \frac{\text{opposite}}{\text{hypotenuse}} sin⁡(52∘)=z7\sin(52^\circ) = \frac{z}{7}
  18. Solve for zz.

    z=7×sin⁡(52∘)z = 7 \times \sin(52^\circ) z≈7×0.7880z \approx 7 \times 0.7880 z≈5.52z \approx 5.52

    The side length is 5.52\boxed{\text{5.52}}.

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