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Find the eighth term and the sum of the first 15 terms of the AP. -7, -4, -1, .........

Mathematics

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Haya, nitakusaidia kutatua maswali haya.

8. Pata neno la nane na jumla ya maneno 15 ya kwanza ya AP: −7,−4,−1,…-7, -4, -1, \dots

  1. Tambua neno la kwanza (aa) na tofauti ya kawaida (dd).

    Neno la kwanza a=−7a = -7.
    Tofauti ya kawaida d=−4−(−7)=−4+7=3d = -4 - (-7) = -4 + 7 = 3.

  2. Pata neno la nane (T8T_8) kwa kutumia fomula Tn=a+(n−1)dT_n = a + (n-1)d.

    T8=−7+(8−1)3T_8 = -7 + (8-1)3 T8=−7+(7)3T_8 = -7 + (7)3 T8=−7+21T_8 = -7 + 21 T8=14T_8 = 14
  3. Pata jumla ya maneno 15 ya kwanza (S15S_{15}) kwa kutumia fomula Sn=n2[2a+(n−1)d]S_n = \frac{n}{2}[2a + (n-1)d].

    S15=152[2(−7)+(15−1)3]S_{15} = \frac{15}{2}[2(-7) + (15-1)3] S15=152[−14+(14)3]S_{15} = \frac{15}{2}[-14 + (14)3] S15=152[−14+42]S_{15} = \frac{15}{2}[-14 + 42] S15=152[28]S_{15} = \frac{15}{2}[28] S15=15×14S_{15} = 15 \times 14 S15=210S_{15} = 210

    Neno la nane ni 14\boxed{14} na jumla ya maneno 15 ya kwanza ni 210\boxed{210}.

    9. Tao la duara, lenye rediasi 10cm, linatengeneza pembe ya 80∘80^\circ katikati ya duara. Pata urefu wa tao.

  4. Tambua rediasi (rr) na pembe (θ\theta).

    Rediasi r=10r = 10 cm.
    Pembe θ=80∘\theta = 80^\circ.

  5. Tumia fomula ya urefu wa tao L=θ360∘×2πrL = \frac{\theta}{360^\circ} \times 2\pi r.

    L=80∘360∘×2×227×10L = \frac{80^\circ}{360^\circ} \times 2 \times \frac{22}{7} \times 10 L=836×2×227×10L = \frac{8}{36} \times 2 \times \frac{22}{7} \times 10 L=29×4407L = \frac{2}{9} \times \frac{440}{7} L=88063L = \frac{880}{63} L≈13.968L \approx 13.968

    Urefu wa tao ni takriban 13.97 cm\boxed{13.97 \text{ cm}}.

    10. Katika trapezi yenye eneo la 40cm240 \text{cm}^2, uwiano wa urefu wa pande sambamba ni 2:32:3. Pata urefu wa pande sambamba ikiwa zimetenganishwa kwa 5cm.

  6. Tambua eneo (AA), uwiano wa pande sambamba, na urefu (hh).

    Eneo A=40cm2A = 40 \text{cm}^2.
    Uwiano wa pande sambamba a:b=2:3a:b = 2:3.
    Urefu h=5h = 5 cm.

  7. Wacha pande sambamba ziwe $2x$ na $3x$.

    Tumia fomula ya eneo la trapezi A=12(a+b)hA = \frac{1}{2}(a+b)h.

    40=12(2x+3x)540 = \frac{1}{2}(2x + 3x)5 40=12(5x)540 = \frac{1}{2}(5x)5 40=25x240 = \frac{25x}{2}
  8. Tatua kwa xx.

    40×2=25x40 \times 2 = 25x 80=25x80 = 25x x=8025x = \frac{80}{25} x=165x = \frac{16}{5} x=3.2x = 3.2
  9. Pata urefu wa pande sambamba.

    Upande wa kwanza a=2x=2×3.2=6.4a = 2x = 2 \times 3.2 = 6.4 cm.
    Upande wa pili b=3x=3×3.2=9.6b = 3x = 3 \times 3.2 = 9.6 cm.

    Urefu wa pande sambamba ni 6.4 cm\boxed{6.4 \text{ cm}} na 9.6 cm\boxed{9.6 \text{ cm}}.

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