Elimination method

Mathematics

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4
2

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Huu ni mfumo wa milinganyo miwili. Tutatumia njia ya kuondoa (elimination method) kutatua.

  1. Andika milinganyo.

    2x+y=10(Mlinganyo 1)2x + y = 10 \quad \text{(Mlinganyo 1)} x−y=2(Mlinganyo 2)x - y = 2 \quad \text{(Mlinganyo 2)}
  2. Ongeza Mlinganyo 1 na Mlinganyo 2.

    Kumbuka kuwa coefficients za yy ni +1+1 na −1-1. Kwa kuongeza milinganyo, yy itaondolewa.

    (2x+y)+(x−y)=10+2(2x + y) + (x - y) = 10 + 2 2x+y+x−y=122x + y + x - y = 12 3x=123x = 12
  3. Tatua kwa xx.

    Gawanya pande zote mbili kwa 3.

    3x3=123\frac{3x}{3} = \frac{12}{3} x=4x = 4
  4. Badilisha thamani ya xx katika mojawapo ya milinganyo asili.

    Tutatumia Mlinganyo 2 (x−y=2x - y = 2) kwa urahisi.

    4−y=24 - y = 2
  5. Tatua kwa yy.

    Toa 4 kutoka pande zote mbili.

    −y=2−4-y = 2 - 4 −y=−2-y = -2

    Zidisha pande zote mbili kwa -1.

    y=2y = 2
  6. Toa majibu.

    Thamani za xx na yy ni 4 na 2 mtawalia.

    Thamani ya xx ni: 4\boxed{4}
    Thamani ya yy ni: 2\boxed{2}

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