Solve the equation: 3y + (5)/(2) = (29 − 21)/(3)

Subtract $\frac{5}{2}$ from both sides:

$$3y = \frac{8}{3} - \frac{5}{2}$$

The least common multiple (LCM) of 3 and 2 is 6.
Rewrite the fractions with the common denominator:

$$3y = \frac{8 \cdot 2}{3 \cdot 2} - \frac{5 \cdot 3}{2 \cdot 3}$$ $$3y = \frac{16}{6} - \frac{15}{6}$$ $$3y = \frac{16 - 15}{6}$$ $$3y = \frac{1}{6}$$

Divide both sides by 3 (or multiply by $\frac{1}{3}$):

$$y = \frac{1}{6} \cdot \frac{1}{3}$$ $$y = \frac{1}{18}$$

The final answer is $\frac{1}{18}$.