Solve the equation 92y imes 2^x = 72 for x and y.

The given equation is $9^{2y} \times 2^x = 72$.
We can write 9 as $3^2$.
We can write 72 as $8 \times 9 = 2^3 \times 3^2$.

For base 3:

This implies that the exponents must be equal:

For base 2:

This implies that the exponents must be equal:

From $4y = 2$:

The values of $x$ and $y$ are: