Determine the equation of a line passing through the point A(6;4) B(2;0)

Mathematics

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Answer

y=x−2y = x - 2

Step-by-step solution

4 steps

Let's determine the equation of the line passing through the points A(6, 4) and B(2, 0).

  1. Calculate the slope (mm) of the line.

    The formula for the slope is m=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1}.
    Let (x1,y1)=(6,4)(x_1, y_1) = (6, 4) and (x2,y2)=(2,0)(x_2, y_2) = (2, 0).

    m=0−42−6m = \frac{0 - 4}{2 - 6} m=−4−4m = \frac{-4}{-4} m=1m = 1
  2. Use the slope-intercept form of a linear equation, y=mx+cy = mx + c.

    Substitute the calculated slope m=1m=1 into the equation:

    y=1x+cy = 1x + c y=x+cy = x + c
  3. Substitute one of the given points into the equation to find the y-intercept (cc).

    Let's use point B(2, 0):

    0=2+c0 = 2 + c c=0−2c = 0 - 2 c=−2c = -2
  4. Write the final equation of the line using the slope and y-intercept.

    y=x−2y = x - 2
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