This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
የያንዳንዱን ርዝመት የእያንዳንዱን የጎን ርዝመት መርምረህ አንዳንዱን እያንዳንዳቸውን አስገባ። ሀ. 7ሴ.ሜ. 4ሴ.ሜ. እና 6ሴ.ሜ. ለ. 8ሴ.ሜ. 8ሴ.ሜ. እና 8ሴ.ሜ. ሐ. 6ሴ.ሜ. 6ሴ.ሜ. እና 10ሴ.ሜ. መ. 2ሴ.ሜ. 9ሴ.ሜ. እና 6ሴ.ሜ. የያንዳንዱን የጎን ርዝመት በሰንጠረዡ መሠረት የጐን ርዝመት 3ሴ.ሜ.: ሀ. 4=6ሴ.ሜ. 4=8ሴ.ሜ. እና 9=9ሴ.ሜ. ለ. <4 =50° : < =50° እና 2.6 = 6ሴ.ሜ.
Mathematics

ScanSolve AI Answer
Answer
: Finding in
Sum of angles in a triangle:
: Finding side in
Law of sines:
,
: Finding side in
Law of sines:
,
: Finding in
Sum of angles in a triangle:
: Finding side in
Law of sines:
,
: Finding side in
Law of sines:
,
Was this helpful?
Need help with your own homework?
Get instant step-by-step solutions to any question. Free to start.
Ask Your QuestionMore Mathematics Questions
QचQर्तियों की सहायता से निम्नांकित का मान ज्ञात कीजिए । (i) (-4)+(-5) (iii) (-11)+(-7) (v) (+4)+(+2)…QKando limited received an invoice from a supplier for K28500. The terms of payment offered were a 5%…QGive me paper one of mathematics kcse 2024 section A questions and answersQPlease Draw Using a ruler and a pair of compases Only construct the following angles 5° 135°QJournal riyazi TCS School maliya malayatti riyasi chapter ka naam hai aur is chapter mein 4.1 exerci…
Still have questions?
Quick Answer
Exercise 1a: Finding A in ABC Sum of angles in a triangle: A = 180^ - B - C A = 180^ - 71^ - 67^ = 42^ A = 42^ Exercise 1b: Finding side b in ABC Law of sines: (a)/( A) = (b)/( B) b = a · ( B)/( A) = 5~cm · ( 71^)/( 42^) 42^ ≈ 0.6694, 71^ ≈ 0.9455 ( 7…
ScanSolve AI Answer
Exercise 1a: Finding A in ABC Sum of angles in a triangle: A = 180^ - B - C A = 180^ - 71^ - 67^ = 42^ A = 42^ Exercise 1b: Finding side b in ABC Law of sines: (a)/( A) = (b)/( B) b = a · ( B)/( A) = 5~cm · ( 71^)/( 42^) 42^ ≈ 0.6694, 71^ ≈ 0.9455 ( 71^)/( 42^) ≈ (0.9455)/(0.6694) ≈ 1.412 b ≈ 5~cm × 1.412 = 7.06~cm b = 7.06~cm Exercise 1c: Finding side c in ABC Law of sines: (a)/( A) = (c)/( C) c = a · ( C)/( A) = 5~cm · ( 67^)/( 42^) 42^ ≈ 0.6694, 67^ ≈ 0.9205 ( 67^)/( 42^) ≈ (0.9205)/(0.6694) ≈ 1.375 c ≈ 5~cm × 1.375 = 6.88~cm c = 6.88~cm Exercise 2a: Finding F in DEF Sum of angles in a triangle: F = 180^ - D - E F = 180^ - 52^ - 67^ = 61^ F = 61^ Exercise 2b: Finding side e in DEF Law of sines: (d)/( D) = (e)/( E) e = d · ( E)/( D) = 10~cm · ( 67^)/( 52^) 52^ ≈ 0.7880, 67^ ≈ 0.9205 ( 67^)/( 52^) ≈ (0.9205)/(0.7880) ≈ 1.168 e ≈ 10~cm × 1.168 = 11.68~cm e = 11.68~cm Exercise 2c: Finding side f in DEF Law of sines: (d)/( D) = (f)/( F) f = d · ( F)/( D) = 10~cm · ( 61^)/( 52^) 52^ ≈ 0.7880, 61^ ≈ 0.8746 ( 61^)/( 52^) ≈ (0.8746)/(0.7880) ≈ 1.110 f ≈ 10~cm × 1.110 = 11.10~cm f = 11.10~cm