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Express 0.78 as a fraction a/b where a,b ∈ Z Expand and Simplify: (7y2 – 6y – 8)(-2y + 2) Factorise the following expressions fully. 3.1 8x2 - 6x + 1 3.2 125x3 + 1

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1.1 Express 0.78‾0.7\overline{8} as a fraction ab\frac{a}{b} where a,b∈Za, b \in \mathbb{Z}

  1. Let xx be the repeating decimal.

    x=0.78‾x = 0.7\overline{8}
  2. Multiply by powers of 10 to isolate the repeating part.

    10x=7.8‾(1)10x = 7.\overline{8} \quad (1) 100x=78.8‾(2)100x = 78.\overline{8} \quad (2)
  3. Subtract equation (1) from equation (2).

    100x−10x=78.8‾−7.8‾100x - 10x = 78.\overline{8} - 7.\overline{8} 90x=7190x = 71
  4. Solve for xx and simplify the fraction.

    x=7190x = \frac{71}{90}

    The fraction is 7190\boxed{\frac{71}{90}}.

    1.2 Expand and Simplify: (7y2−6y−8)(−2y+2)(7y^2 - 6y - 8)(-2y + 2)

  5. Distribute each term from the first polynomial to each term in the second polynomial.

    =7y2(−2y)+7y2(2)−6y(−2y)−6y(2)−8(−2y)−8(2)= 7y^2(-2y) + 7y^2(2) - 6y(-2y) - 6y(2) - 8(-2y) - 8(2)
  6. Perform the multiplications.

    =−14y3+14y2+12y2−12y+16y−16= -14y^3 + 14y^2 + 12y^2 - 12y + 16y - 16
  7. Combine like terms.

    =−14y3+(14y2+12y2)+(−12y+16y)−16= -14y^3 + (14y^2 + 12y^2) + (-12y + 16y) - 16 =−14y3+26y2+4y−16= -14y^3 + 26y^2 + 4y - 16

    The expanded and simplified expression is −14y3+26y2+4y−16\boxed{-14y^3 + 26y^2 + 4y - 16}.

    1.3 Factorise the following expressions fully.

    1.3.1 8x2−6x+18x^2 - 6x + 1

  8. Find two numbers that multiply to 8×1=88 \times 1 = 8 and add up to −6-6.

    These numbers are −2-2 and −4-4.

  9. Rewrite the middle term using these two numbers.

    8x2−2x−4x+18x^2 - 2x - 4x + 1
  10. Factor by grouping.

    2x(4x−1)−1(4x−1)2x(4x - 1) - 1(4x - 1)
  11. Factor out the common binomial factor (4x−1)(4x - 1).

    (2x−1)(4x−1)(2x - 1)(4x - 1)

    The factorised expression is (2x−1)(4x−1)\boxed{(2x - 1)(4x - 1)}.

    1.3.2 125x3+1125x^3 + 1

  12. Recognize this as a sum of cubes, which follows the formula a3+b3=(a+b)(a2−ab+b2)a^3 + b^3 = (a+b)(a^2 - ab + b^2).

  13. Identify aa and bb.

    a3=125x3  ⟹  a=5xa^3 = 125x^3 \implies a = 5x b3=1  ⟹  b=1b^3 = 1 \implies b = 1
  14. Substitute aa and bb into the sum of cubes formula.

    (5x+1)((5x)2−(5x)(1)+(1)2)(5x + 1)((5x)^2 - (5x)(1) + (1)^2)
  15. Simplify the terms.

    (5x+1)(25x2−5x+1)(5x + 1)(25x^2 - 5x + 1)

    The factorised expression is (5x+1)(25x2−5x+1)\boxed{(5x + 1)(25x^2 - 5x + 1)}.

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