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Express as a single fraction: 2 rac12 + 3 rac14 rdiv 2 rac16 - 1 rac16

Mathematics

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2. Express as a single fraction: 212+314÷216−1162\frac{1}{2} + 3\frac{1}{4} \div 2\frac{1}{6} - 1\frac{1}{6}

  1. Convert all mixed numbers to improper fractions.

    212=522\frac{1}{2} = \frac{5}{2} 314=1343\frac{1}{4} = \frac{13}{4} 216=1362\frac{1}{6} = \frac{13}{6} 116=761\frac{1}{6} = \frac{7}{6}

    The expression becomes:

    52+134÷136−76\frac{5}{2} + \frac{13}{4} \div \frac{13}{6} - \frac{7}{6}
  2. Perform the division first, following the order of operations.

    134÷136=134×613=64=32\frac{13}{4} \div \frac{13}{6} = \frac{13}{4} \times \frac{6}{13} = \frac{6}{4} = \frac{3}{2}

    The expression is now:

    52+32−76\frac{5}{2} + \frac{3}{2} - \frac{7}{6}
  3. Perform the addition and subtraction from left to right.

    52+32=5+32=82=4\frac{5}{2} + \frac{3}{2} = \frac{5+3}{2} = \frac{8}{2} = 4

    The expression is now:

    4−764 - \frac{7}{6}
  4. Subtract the fraction.

    4−76=246−76=24−76=1764 - \frac{7}{6} = \frac{24}{6} - \frac{7}{6} = \frac{24-7}{6} = \frac{17}{6}

    The final answer is:

    176\boxed{\frac{17}{6}}

    3. By rationalizing the denominator, express A=3−21+2A = \frac{3-\sqrt{2}}{1+\sqrt{2}} into the form a+b2a + b\sqrt{2} where aa and bb are constants.

  5. Identify the conjugate of the denominator.

    The denominator is 1+21+\sqrt{2}. Its conjugate is 1−21-\sqrt{2}.

  6. Multiply the numerator and denominator by the conjugate.

    A=3−21+2×1−21−2A = \frac{3-\sqrt{2}}{1+\sqrt{2}} \times \frac{1-\sqrt{2}}{1-\sqrt{2}}
  7. Expand the numerator and denominator.

    Numerator: (3−2)(1−2)=3(1)+3(−2)−2(1)−2(−2)(3-\sqrt{2})(1-\sqrt{2}) = 3(1) + 3(-\sqrt{2}) - \sqrt{2}(1) - \sqrt{2}(-\sqrt{2})

    =3−32−2+(2)2= 3 - 3\sqrt{2} - \sqrt{2} + (\sqrt{2})^2 =3−42+2= 3 - 4\sqrt{2} + 2 =5−42= 5 - 4\sqrt{2}

    Denominator: (1+2)(1−2)=12−(2)2(1+\sqrt{2})(1-\sqrt{2}) = 1^2 - (\sqrt{2})^2

    =1−2= 1 - 2 =−1= -1
  8. Combine the simplified numerator and denominator and express in the form a+b2a+b\sqrt{2}.

    A=5−42−1A = \frac{5 - 4\sqrt{2}}{-1} A=−5+42A = -5 + 4\sqrt{2}

    Comparing this to a+b2a+b\sqrt{2}, we have a=−5a=-5 and b=4b=4.
    The final answer is:

    −5+42\boxed{-5 + 4\sqrt{2}}
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