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Evaluate the expression 3x3 + 4x2 - x + 2, if x = -2. In the right-angled triangle below, angle QPR is x. Find (x) and (x).

Mathematics

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Answers

2 parts
i

35\frac{3}{5}

ii

43\frac{4}{3}

Step-by-step solution

6 steps

here are the solutions to the questions.

Evaluate the expression: 3x3+4x2−x+23x^3 + 4x^2 - x + 2, if x=−2x = -2.

Step 1: Substitute x=−2x = -2 into the expression.

3(−2)3+4(−2)2−(−2)+23(-2)^3 + 4(-2)^2 - (-2) + 2

Step 2: Calculate the powers of −2-2.

(−2)3=−8(-2)^3 = -8 (−2)2=4(-2)^2 = 4

Step 3: Substitute these values back into the expression.

3(−8)+4(4)−(−2)+23(-8) + 4(4) - (-2) + 2

Step 4: Perform the multiplications.

−24+16+2+2-24 + 16 + 2 + 2

Step 5: Perform the additions and subtractions.

−8+2+2-8 + 2 + 2 −6+2-6 + 2 −4-4

The value of the expression is −4\boxed{-4}.

In the right-angled triangle below, angle QPR is xx. From the diagram, find the following:
The triangle has sides:
Hypotenuse (PR) = 15
Adjacent to xx (PQ) = 9
Opposite to xx (RQ) = 12

Part i· 3 steps

cos⁡(x)\cos(x)

  1. Use the definition of cosine

    cos⁡(x)=AdjacentHypotenuse\cos(x) = \frac{\text{Adjacent}}{\text{Hypotenuse}}. cos⁡(x)=PQPR \cos(x) = \frac{PQ}{PR}

  2. Substitute the side lengths.

    $$
    \cos(x) = \frac{9}{15}
    $$
    
  3. Simplify the fraction.

    $$
    \cos(x) = \frac{3}{5}
    $$
    $$
    \cos(x) = \boxed{\frac{3}{5}}
    $$
    

Part ii

43\frac{4}{3}

tan⁡(x)\tan(x)

  1. Use the definition of tangent

    tan⁡(x)=OppositeAdjacent\tan(x) = \frac{\text{Opposite}}{\text{Adjacent}}. tan⁡(x)=RQPQ \tan(x) = \frac{RQ}{PQ}

  2. Substitute the side lengths.

    $$
    \tan(x) = \frac{12}{9}
    $$
    
  3. Simplify the fraction.

    $$
    \tan(x) = \frac{4}{3}
    $$
    $$
    \tan(x) = \boxed{\frac{4}{3}}
    $$
    
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