Alright Nurse — let's do this.
The function is given by f(x)=x−5x2−25.
Step 1: Factor the numerator. The numerator is a difference of squares, x2−25=(x−5)(x+5).
f(x)=x−5(x−5)(x+5)
Step 2: Cancel out the common factor (x−5) from the numerator and denominator, assuming x=5.
f(x)=x+5,forx=5
The function f(x) simplifies to x+5 for all values of x except x=5. At x=5, the original function is undefined.
The simplified expression for f(x) is x+5.
f(x) = x + 5, \text{ for x \neq 5}
What's next?