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Factorise the following completely: 1) 10x2 - 9xy + 2y2, 2) 5x2 + 18xy + 9y2

Mathematics

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Here's how to factorize the given expressions:

1) Factorize 10x2−9xy+2y210x^2 - 9xy + 2y^2

  1. Find two numbers that multiply to 10×2=2010 \times 2 = 20 and add up to −9-9.

    These numbers are −4-4 and −5-5. Rewrite the middle term using these numbers.

    10x2−9xy+2y2=10x2−5xy−4xy+2y210x^2 - 9xy + 2y^2 = 10x^2 - 5xy - 4xy + 2y^2
  2. Group the terms and factor out the common factors from each group.

    (10x2−5xy)−(4xy−2y2)(10x^2 - 5xy) - (4xy - 2y^2) 5x(2x−y)−2y(2x−y)5x(2x - y) - 2y(2x - y)
  3. Factor out the common binomial (2x−y)(2x - y).

    (5x−2y)(2x−y)(5x - 2y)(2x - y)

    The factored expression is (5x−2y)(2x−y)\boxed{(5x - 2y)(2x - y)}.

    2) Factorize 5x2+18xy+9y25x^2 + 18xy + 9y^2

  4. Find two numbers that multiply to 5×9=455 \times 9 = 45 and add up to 18.

    These numbers are 3 and 15. Rewrite the middle term using these numbers.

    5x2+18xy+9y2=5x2+3xy+15xy+9y25x^2 + 18xy + 9y^2 = 5x^2 + 3xy + 15xy + 9y^2
  5. Group the terms and factor out the common factors from each group.

    (5x2+3xy)+(15xy+9y2)(5x^2 + 3xy) + (15xy + 9y^2) x(5x+3y)+3y(5x+3y)x(5x + 3y) + 3y(5x + 3y)
  6. Factor out the common binomial (5x+3y)(5x + 3y).

    (x+3y)(5x+3y)(x + 3y)(5x + 3y)

    The factored expression is (x+3y)(5x+3y)\boxed{(x + 3y)(5x + 3y)}.

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