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Factorize the algebraic expression 3x2 + 7x - 12x - 34 - 2x2 + 10

Mathematics

ScanSolve AI Answer

Answer

(x+3)(x-8)

Step-by-step solution

4 steps

Here is a step-by-step guide on how to factorize the algebraic expression 3x2+7x−12x−34−2x2+103x^2 + 7x - 12x - 34 - 2x^2 + 10:

  1. Combine like terms*.

    Identify and group terms that have the same variable and exponent.

    (3x2−2x2)+(7x−12x)+(−34+10)(3x^2 - 2x^2) + (7x - 12x) + (-34 + 10)
  2. Simplify the expression*.

    Perform the addition and subtraction for each group of like terms.

    (3−2)x2+(7−12)x+(−34+10)(3-2)x^2 + (7-12)x + (-34+10) 1x2−5x−241x^2 - 5x - 24

    The simplified expression is x2−5x−24x^2 - 5x - 24.

  3. Identify two numbers that multiply to the constant term and add to the coefficient of the middle term*.

    For the quadratic trinomial x2−5x−24x^2 - 5x - 24, we need two numbers that:

    • Multiply to −24-24 (the constant term).
    • Add up to −5-5 (the coefficient of the xx term). Let's consider factors of −24-24: 1×(−24)=−241 \times (-24) = -24, 1+(−24)=−231 + (-24) = -23 2×(−12)=−242 \times (-12) = -24, 2+(−12)=−102 + (-12) = -10 3×(−8)=−243 \times (-8) = -24, 3+(−8)=−53 + (-8) = -5 The two numbers are 3 and −8-8.
  4. Write the expression in factored form*.

    Using the two numbers found in Step 3, the trinomial x2−5x−24x^2 - 5x - 24 can be factored as (x+first number)(x+second number)(x + \text{first number})(x + \text{second number}).

    (x+3)(x−8)(x + 3)(x - 8)
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